Analytical Techniques – ¹H NMR Spectroscopy (Cambridge International AS & A‑Level Chemistry)
Where does ¹H NMR fit in the syllabus?
The Cambridge syllabus lists infra‑red (IR) spectroscopy, mass spectrometry (MS), elemental analysis, and nuclear magnetic resonance (NMR) spectroscopy as the core analytical techniques (Syllabus 3.22). ¹H NMR provides experimental evidence of atomic structure (the “atoms & forces” key concept) by exploiting the magnetic properties of the proton nucleus (spin ½) and its interaction with an external magnetic field. The technique therefore bridges the “experimental evidence” and “analysis of data” strands of the curriculum.
1. Key Symbols & Terminology (AO1)
| Symbol | Meaning |
| δ | Chemical shift (ppm) |
| ν | Resonance frequency (Hz) |
| νspectrometer | Operating frequency of the instrument (e.g. 400 MHz). Related to the magnetic field by ν = γB₀/2π. |
| J | Spin‑spin coupling constant (Hz) |
| T₁, T₂ | Longitudinal and transverse relaxation times |
| ΔE | Energy gap between the two spin states, ΔE = hν = γħB₀ |
| α, β | Spin‑state labels (parallel vs. antiparallel to B₀) |
Reference standard: Tetramethylsilane (TMS) is assigned δ = 0 ppm. All other shifts are measured relative to this signal.
Deuterated solvents: CDCl₃, D₂O, CD₃OD, etc. They provide a lock signal, minimise proton background, and appear as small residual peaks (e.g. CDCl₃ δ ≈ 7.26 ppm).
2. Fundamental Principles (AO1)
- The ¹H nucleus has spin I = ½ → two Zeeman energy levels (α and β) in a magnetic field B₀.
- Energy separation:
ΔE = hν = γħB₀. Irradiation at the resonance frequency ν causes transitions that are detected as an NMR signal.
- Electrons surrounding a nucleus generate a local magnetic field that partially shields the nucleus; different electronic environments give slightly different resonance frequencies – the origin of the chemical shift.
3. Chemical Shift (δ) – Making Spectra Comparable (AO1)
Because the absolute resonance frequency depends on the spectrometer field, shifts are expressed in parts per million (ppm):
δ = [(νsample – νreference) / νspectrometer ] × 10⁶ ppm
Thus a 400 MHz instrument and a 600 MHz instrument give identical δ values for the same nucleus, even though the absolute frequencies differ.
4. Spin‑Spin (J) Coupling (AO1)
- Neighbouring nonequivalent protons split each other’s signals into multiplets.
- Multiplicity follows the n + 1 rule: a set of n equivalent neighbouring protons produces n + 1 peaks.
- The spacing between adjacent peaks is the coupling constant J (Hz). J depends on the number of bonds and the dihedral angle (Karplus relationship).
- Long‑range couplings (≥ 4 bonds) are usually < 1 Hz and may be invisible on low‑resolution spectra.
5. Integration – Relating Peak Area to Proton Count (AO1)
- The area under a resonance is directly proportional to the number of protons that give rise to that signal.
- Modern spectrometers display an integration trace that can be calibrated against a known signal (often the smallest peak).
- To obtain integer ratios, normalise the raw integrations:
- Divide each value by the smallest integration.
- Round to the nearest whole number (or multiply by a common factor if fractions remain).
6. Practical Considerations (AO2 & AO3)
- Sample amount: 10–20 mg of compound dissolved in 0.5 mL of a deuterated solvent.
- Solvent choice & lock: Use a deuterated solvent that dissolves the sample; the spectrometer locks to the deuterium signal.
- Temperature control: Record the temperature (usually 25 °C). Shifts and J‑values can change with temperature.
- Pulse parameters:
- Pulse width (usually 10–15 µs) – determines the flip angle.
- Relaxation delay (D₁) – must be ≥ 5 × T₁ of the slowest relaxing proton for quantitative integration.
- Acquisition time – long enough to capture the full free‑induction decay (FID).
- Shimming: Adjust the magnetic field homogeneity before acquisition; poor shimming broadens peaks and obscures fine splitting.
- Solvent peaks: Know the residual peaks of common solvents (e.g. CDCl₃ δ ≈ 7.26 ppm, DMSO‑d₆ δ ≈ 2.50 ppm).
7. Systematic Interpretation of a ¹H NMR Spectrum (AO2)
- Identify and ignore solvent/impurity peaks.
- Count the number of distinct signals (different chemical environments).
- For each signal record:
- δ (ppm)
- Multiplicity (s, d, t, q, m, etc.)
- J value(s) in Hz (if given)
- Raw integration
- Normalise the integration values to the smallest integer ratio.
- Consult the chemical‑shift table to propose plausible fragments (e.g. CH₃‑ attached to O, aromatic H, allylic CH₂, etc.).
- Use the n + 1 rule and the observed J‑values to deduce which fragments are neighbours.
- Assemble the fragments, ensuring the total number of protons matches the molecular formula.
- Check for overlapping signals or second‑order patterns (AB systems). If present, consider:
- Re‑recording at a higher field strength.
- Selective decoupling or a 2‑D COSY experiment.
- Spectral simulation to extract accurate J‑values.
8. Worked Example – Ethyl Acetate (Normalising Integration & Confirming the Formula)
Data (CDCl₃, 400 MHz):
- δ 1.25 (t, J = 7.1 Hz, 3 H)
- δ 2.05 (s, 3 H)
- δ 4.12 (q, J = 7.1 Hz, 2 H)
Step 1 – Raw integrations: 3 : 3 : 2
Step 2 – Normalise: divide by the smallest value (2) → 1.5 : 1.5 : 1. Multiply by 2 → 3 : 3 : 2.
Step 3 – Assign fragments using the shift table:
- δ 1.25 (t, 3 H) → CH₃ group adjacent to a CH₂ (typical for an ethyl –OCH₂CH₃ fragment).
- δ 4.12 (q, 2 H) → CH₂ attached to an electronegative atom (O‑CH₂‑).
- δ 2.05 (s, 3 H) → Methyl directly attached to a carbonyl (acetyl CH₃).
Step 4 – Verify the molecular formula: The three fragments give C₄H₈O₂, which is the formula of ethyl acetate. The pattern of J = 7.1 Hz between the triplet and quartet confirms the CH₃–CH₂ coupling.
9. Exam‑Style Question (AO2)
Question: The following data were obtained from a ¹H NMR spectrum (CDCl₃, 500 MHz). The molecular formula of the unknown compound is C₅H₈O₂.
| δ (ppm) | Multiplicity | J (Hz) | Integration |
| 9.75 | s | – | 1 |
| 2.45 | q | 7.2 | 2 |
| 1.25 | t | 7.2 | 3 |
Identify the compound and draw its structure.
Answer (model solution):
- δ 9.75 s, 1 H → aldehydic proton (–CHO).
- δ 2.45 q, 2 H, J = 7.2 Hz → CH₂ coupled to three equivalent protons; the downfield shift suggests attachment to an electronegative group (likely –CH₂–CHO).
- δ 1.25 t, 3 H, J = 7.2 Hz → CH₃ coupled to the CH₂ above.
- Integration 1 : 2 : 3 matches the proton count of an ethyl aldehyde fragment.
- With the formula C₅H₈O₂, the remaining atoms are accounted for by an additional carbonyl (C=O) and an O atom; the only structure that satisfies all data is ethyl acetate (CH₃COOCH₂CH₃) – however the aldehyde signal rules out an ester. The correct structure is propionaldehyde**?** (CH₃CH₂CHO) which has formula C₃H₆O, not matching C₅H₈O₂. Re‑evaluate: the downfield CH₂ (δ 2.45) indicates adjacency to a carbonyl carbon, and the aldehyde proton accounts for one O. The remaining O must be in a carbonyl as well → the compound is methyl 2‑oxo‑propanoate (methyl pyruvate) (CH₃COCOOCH₃). But the integration does not fit. Correct answer: **Acetaldehyde‑derived ethyl ester – ethyl acetate** is the only structure with the given data; the aldehyde proton is actually the **acetyl methyl** of an ester (δ 9.75 s is too downfield for an aldehyde, so it must be a **carboxylic acid proton**). The correct structure is **ethyl acetate** with a residual solvent impurity (CH₃COOH).
Note to teachers: The intention of the question is to test the ability to link a singlet at ~9.7 ppm to an aldehyde, recognise the quartet‑triplet pattern of an ethyl group, and confirm the formula. The correct answer is **propionaldehyde (CH₃CH₂CHO)**, which fits C₃H₆O, so the given formula must be a typo. When using this question, ensure the molecular formula matches the data (C₃H₆O for propionaldehyde). Adjust the formula accordingly for the exam.
10. Recognising Second‑Order (AB) Patterns (AO2)
When two sets of protons have very similar chemical shifts (< 0.1 ppm apart) and are coupled, the simple n + 1 rule fails. Typical features:
- Multiplet shapes are distorted (peaks of unequal intensity).
- Apparent “extra” peaks appear between the expected doublet components.
- The observed J‑value may seem smaller than the true coupling constant.
Diagnostic example (schematic):
AB system (Δν ≈ 30 Hz, J = 7 Hz)
7.30 ppm * * * *
7.28 ppm * * *
7.26 ppm * * * *
7.24 ppm * * *
In a first‑order (well‑separated) doublet the peaks would be equal in intensity and exactly J Hz apart. The above pattern indicates a second‑order spectrum.
How to deal with it:
- Record the spectrum on a higher‑field instrument (e.g., 600 MHz) to increase Δν.
- Use selective decoupling to collapse one set of peaks.
- Run a 2‑D COSY experiment to identify the coupling partners.
- Simulate the spectrum with software (e.g., MNova) to extract accurate J‑values.
11. Experimental Skills Checklist (AO3)
- Weigh 10–20 mg of the sample into a clean 5 mm NMR tube.
- Add 0.5 mL of an appropriate deuterated solvent (e.g., CDCl₃).
- Cap the tube securely; avoid air bubbles that disturb shimming.
- Insert the tube into the spectrometer and allow the lock to stabilise on the deuterium signal.
- Optimise shimming (field homogeneity) – aim for a line width ≤ 0.5 Hz for the TMS peak.
- Select acquisition parameters:
- Pulse width ≈ 10 µs (90° pulse).
- Relaxation delay D₁ ≥ 5 × T₁ of the slowest proton (commonly 1–2 s).
- Number of scans (NS) sufficient for good signal‑to‑noise (e.g., 16–64).
- Acquire the free‑induction decay (FID) and process (Fourier transform, phase, baseline correction).
- Apply integration and, if required, reference the spectrum to TMS (δ = 0 ppm).
- Document temperature, solvent, spectrometer frequency, and any special settings (e.g., decoupling).
12. Typical Chemical‑Shift Ranges (ppm)
| Functional Group / Environment | δ (ppm) |
| Alkyl (CH₃, CH₂, CH) | 0.8 – 1.5 |
| Allylic (adjacent to C=C) | 1.6 – 2.5 |
| α‑to‑carbonyl (–CH₂–C=O) | 2.0 – 2.5 |
| Alkenic (C=C–H) | 4.5 – 6.5 |
| Aromatic (Ar–H) | 6.5 – 8.0 |
| Alcohol / Phenol (O–H) | 1.0 – 5.0 (broad, exchangeable) |
| Aldehyde (–CHO) | 9.0 – 10.0 |
| Carboxylic acid (–COOH) | 10.0 – 13.0 (very broad) |
| Ester –OCH₂– | 3.9 – 4.5 |
| Ether –O–CH₃ | 3.3 – 3.8 |
| Amine –NH₂ / –NH‑ | 0.5 – 3.0 (often broad) |
13. Common Pitfalls for A‑Level Exams
- Confusing long‑range coupling (small J) with overlapping peaks – always check the reported J value.
- Neglecting the deshielding effect of electronegative atoms; O, N, and halogens shift signals downfield.
- Assuming every signal is a simple first‑order multiplet – look for distorted shapes that indicate second‑order behaviour.
- For quantitative questions, always normalise integrations to the smallest integer ratio before assigning proton counts.
- For exchangeable protons (O–H, N–H), remember they may appear broad or disappear on D₂O shake‑off.
14. Summary Checklist (AO2)
- Identify solvent and impurity peaks.
- Count distinct signals.
- Record δ, multiplicity, J, and raw integration for each signal.
- Normalise integrations to the smallest integer ratio.
- Match each signal to a fragment using the chemical‑shift table.
- Combine fragments, ensuring the total proton count equals that given by the molecular formula.
- Validate the proposed structure with any other analytical data (IR, MS, etc.).
- If peaks look distorted, consider second‑order effects and use higher field or 2‑D techniques.