Chemical energetics: enthalpy changes, bond energies, Hess’s law, calorimetry

Chemical Energetics (Cambridge AS & A‑Level Chemistry 9701)

1. Enthalpy (ΔH)

  • Definition: The heat exchanged with the surroundings when a process occurs at constant pressure. ΔH is a state function – only the initial and final states matter.
  • Sign convention
    • Exothermic: ΔH < 0 (heat released to the surroundings).
    • Endothermic: ΔH > 0 (heat absorbed from the surroundings).
  • Standard enthalpy change (ΔH°): Measured under the standard state
    • Temperature: 298 K (25 °C)
    • Pressure: 101 kPa (1 atm)
    • All reactants and products at a concentration of 1 mol L⁻¹ (or 1 atm for gases).

1.1 Types of Standard Enthalpy Changes

Symbol Name Definition (standard state) Typical example
ΔH°f Standard enthalpy of formation Enthalpy change when 1 mol of a compound is formed from its constituent elements in their standard states. H₂(g) + ½ O₂(g) → H₂O(l)
ΔH°c Standard enthalpy of combustion Enthalpy change when 1 mol of a substance burns completely in excess O₂ under standard conditions. CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(l)
ΔH°neut Standard enthalpy of neutralisation Enthalpy change when 1 mol of H⁺ reacts with 1 mol of OH⁻ to give liquid water (standard conditions). HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
ΔH°r Standard enthalpy of reaction Overall enthalpy change for any reaction, calculated from ΔH°f values of reactants and products. Any balanced equation, e.g. the combustion of propane.

1.2 Example – Standard Enthalpy of Neutralisation

For the reaction HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l) the measured heat released is –57 kJ per mole of water formed. Hence, ΔH°neut = –57 kJ mol⁻¹.

2. Bond Energies

  • Bond dissociation energy (average bond enthalpy): Energy required to break one mole of a particular bond in the gas phase.
  • Values are averages because the energy varies with the molecular environment; they are best used for quick estimates.
  • Estimating reaction enthalpy:

    ΔHrxn ≈ ∑ Ebroken − ∑ Eformed

  • Limitations
    • Applicable only to gaseous species (bond energies are defined for gas‑phase molecules).
    • Ignores phase changes, hydrogen bonding, resonance and other electronic effects.
    • Provides an approximation; for accurate values use ΔH°f data or calorimetry.
BondBond energy (kJ mol⁻¹) BondBond energy (kJ mol⁻¹)
C–C347C=O799
C–H413O–H463
H–H436N≡N945
Cl–Cl242O=O498

3. Hess’s Law

Because enthalpy is a state function, the total ΔH for a reaction is independent of the pathway taken. This allows us to combine known enthalpy changes to obtain the ΔH for a reaction that is difficult to measure directly.

Mathematical form:

ΔHoverall = ∑ ΔHi

Steps to apply Hess’s Law

  1. Write the target reaction clearly.
  2. Identify standard enthalpies (ΔH°f, ΔH°c, ΔH°neut, etc.) that are available.
  3. Manipulate the known equations (reverse, multiply by a coefficient) so that, when added, unwanted species cancel and the desired reaction remains.
  4. Sum the adjusted ΔH values – the result is ΔH° for the target reaction.
Reactants (A) Products (D) Intermediates (B, C) ΔH₁ ΔH₂ ΔH₃ ΔH₄
Hess’s law cycle – the sum of enthalpy changes around any closed loop is zero.

4. Calorimetry

4.1 Constant‑pressure (coffee‑cup) calorimeter

At constant pressure the heat exchanged equals the enthalpy change of the reaction:

qrxn = −qsolution = −m c ΔT

  • m – mass of the solution (≈ mass of water, in g).
  • c – specific heat capacity of water (4.18 J g⁻¹ K⁻¹).
  • ΔT – final temperature − initial temperature (K or °C).

To obtain the molar enthalpy change:

ΔH = qrxn / n (kJ mol⁻¹)

4.2 Practical considerations

  • Determine the calorimeter’s heat capacity (Ccal) by a calibration experiment. Then include it:

    qtotal = CcalΔT + m c ΔT

  • Use a well‑insulated cup to minimise heat loss; if loss is significant, apply a correction.
  • Assume all reactants and products reach the same final temperature.

4.3 Constant‑volume (bomb) calorimeter (optional for A‑Level)

At constant volume the heat exchanged equals the change in internal energy (ΔU):

qrxn = −CcalΔT = ΔU

For reactions involving gases, ΔH can be obtained from ΔU using:

ΔH = ΔU + ΔngRT

where Δng is the change in the number of moles of gas.

5. Standard Enthalpies of Formation (ΔH°f)

ΔH°f is the enthalpy change for forming 1 mol of a compound from its elements in their standard states. By definition, ΔH°f = 0 for any element in its standard state.

CompoundΔH°f (kJ mol⁻¹) CompoundΔH°f (kJ mol⁻¹)
H₂O(l)-285.8CO₂(g)-393.5
CH₄(g)-74.8NH₃(g)-46.1
C₂H₆(g)-84.0SO₂(g)-296.8
H₂(g)0O₂(g)0

Using ΔH°f values, the standard enthalpy change for any reaction is:

ΔH°rxn = ∑ ΔH°f, products − ∑ ΔH°f, reactants

6. Worked Example – Enthalpy of Combustion of Propane

Reaction (standard conditions)

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l)

ΔH°f values (kJ mol⁻¹)

  • ΔH°f(C₃H₈) = –104.7
  • ΔH°f(O₂) = 0
  • ΔH°f(CO₂) = –393.5
  • ΔH°f(H₂O(l)) = –285.8

Calculation

\[ \Delta H^\circ_{\text{comb}} = [3(-393.5) + 4(-285.8)] - [(-104.7) + 5(0)] \] \[ \Delta H^\circ_{\text{comb}} = (-1180.5 - 1143.2) - (-104.7) = -2323.7 + 104.7 = -2219.0\ \text{kJ mol}^{-1} \]

The combustion of one mole of propane releases 2219 kJ** under standard conditions.

7. Summary Checklist (What to Remember)

  • ΔH is measured at constant pressure; ΔU at constant volume.
  • Standard state: 298 K, 101 kPa (1 atm), 1 mol L⁻¹ (or 1 atm for gases).
  • ΔH°f values are the basis for calculating any ΔH°r.
  • ΔH°c and ΔH°neut are special cases of ΔH°r.
  • Bond‑energy method gives a quick estimate: ΔH ≈ ΣEbroken − ΣEformed.
  • Hess’s law lets you combine known enthalpy changes to find an unknown ΔH.
  • In a coffee‑cup calorimeter: q = –m c ΔT; ΔH = q / n.
  • For bomb calorimetry: q = –CcalΔT = ΔU; convert to ΔH with ΔH = ΔU + ΔngRT if required.

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