Information Technology IT – 21 Programming for the web | e-Consult

Answer: Here's a JavaScript function that filters an array of numbers to return a new array containing only the even numbers, using a for...of loop:

Function:

function getEvenNumbers(numbers) {
const evenNumbers = [];
for (const number of numbers) {
if (number % 2 === 0) {
evenNumbers.push(number);
}
}
return evenNumbers;
}

Explanation:

• The function getEvenNumbers accepts an array of numbers called numbers as input.
• It initializes an empty array called evenNumbers to store the even numbers.
• The for...of loop iterates through each number in the numbers array.
• Inside the loop, the if statement checks if the current number is even by using the modulo operator %. If number % 2 is equal to 0, it means the number is divisible by 2 and is therefore even.
• If the number is even, it's added to the evenNumbers array using the push() method.
• Finally, the function returns the evenNumbers array, which contains only the even numbers from the input array.

Example Usage:

const numbers = [1, 2, 3, 4, 5, 6];
const evenNumbers = getEvenNumbers(numbers);
console.log(evenNumbers); // Output: [2, 4, 6]