Additional Mathematics – Quadratic functions | e-Consult
Quadratic functions (1 questions)
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Answer 2
Differentiate:
\(g'(x) = -6x + 12\).
Set derivative to zero:
\(-6x + 12 = 0 \;\Rightarrow\; x = 2\).
Second derivative \(g''(x) = -6
Evaluate \(g(2)\):
\(g(2) = -3(2)^{2} + 12(2) - 7 = -12 + 24 - 7 = 5\).
Maximum value: \(\displaystyle g_{\max}=5\) at \(x=2\).