Additional Mathematics – Permutations and combinations | e-Consult
Permutations and combinations (1 questions)
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Answer: Because the arrangement (order) of the letters is important, this is a permutation problem.
\[
P(26,5)=\frac{26!}{(26-5)!}=26\times25\times24\times23\times22=7\,893\,600
\]
Hence, there are 7,893,600 possible passwords.