Physics – 6.2.3 The Universe | e-Consult

Using the distance modulus formula: m - M = 5 log₁₀(d) - 5

We are given: m = 15.2 and M = -18.5

Substitute these values into the formula:

15.2 - (-18.5) = 5 log₁₀(d) - 5

33.7 = 5 log₁₀(d) - 5

38.7 = 5 log₁₀(d)

7.74 = log₁₀(d)

d = 10^7.74

d ≈ 425 parsecs

Therefore, the distance to the supernova is approximately 425 parsecs.