Physics – 4.5.4 Force on a current-carrying conductor | e-Consult

The force on a charged particle in a magnetic field is given by the formula: F = qvBsinθ, where:

• F is the magnitude of the force (in Newtons)
• q is the magnitude of the charge (in Coulombs)
• v is the speed of the particle (in m/s)
• B is the magnitude of the magnetic field (in Tesla)
• θ is the angle between the velocity vector and the magnetic field vector.

In this case, the velocity and magnetic field are perpendicular, so θ = 90 degrees and sin(90°) = 1.

Therefore, F = (1.60 x 10^-19 C) * (2.0 x 10⁶ m/s) * (0.40 T) * 1

F = 1.28 x 10^-18 N

The magnitude of the force experienced by each electron is 1.28 x 10^-18 N.