Physics – 4.5.4 Force on a current-carrying conductor | e-Consult
4.5.4 Force on a current-carrying conductor (1 questions)
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Formula: The magnitude of the magnetic force (F) on a current-carrying conductor in a magnetic field is given by:
F = I x L x B x sin(θ)
where:
- I = Current (in Amperes)
- L = Length of the conductor in the magnetic field (in meters)
- B = Magnetic field strength (in Teslas)
- θ = Angle between the current and the magnetic field
Calculation:
I = 2 A
L = 0.2 m
B = 0.5 T
θ = 90° (since the wire is perpendicular to the magnetic field), sin(90°) = 1
F = 2 A x 0.2 m x 0.5 T x 1 = 0.2 N
Answer: The magnitude of the magnetic force is 0.2 N.