Physics – 4.5.4 Force on a current-carrying conductor | e-Consult
4.5.4 Force on a current-carrying conductor (1 questions)
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Formula: The magnetic force on a current-carrying loop is given by:
F = N x I x A x sin(θ)
where:
- N = Number of turns in the loop (assumed to be 1 for a single loop)
- I = Current (in Amperes)
- A = Area of the loop (in m2)
- θ = Angle between the magnetic field and the normal to the loop (which is 90° in this case)
Calculations:
N = 1
I = 5 A
A = length x width = 0.5 m x 0.3 m = 0.15 m2
θ = 90°
F = 1 x 5 A x 0.15 m2 x 1 = 0.75 N
Answer: The magnitude of the magnetic force acting on the loop is 0.75 N.