Physics – 2.2.2 Specific heat capacity | e-Consult

Solution:

1. Calculate the energy supplied by the heater: Energy (E) = Power (P) x Time (t)

   E = 100 W x 60 s = 6000 J

2. Use the formula for thermal energy transfer: Q = mcΔT, where:

   Q = Thermal energy transferred (equal to the increase in internal energy)

   m = mass of the copper block (25.0 g)

   c = specific heat capacity of copper (0.385 J/g°C)

   ΔT = change in temperature (T_final - T_initial)

3. Rearrange the formula to solve for ΔT: ΔT = Q / (mc)

   ΔT = 6000 J / (25.0 g x 0.385 J/g°C)

   ΔT = 6000 / 9.625 ≈ 625.5 °C

4. The increase in internal energy is equal to the thermal energy transferred, which is 6000 J.

   Therefore, the increase in internal energy of the copper block is 6000 J.