Physics – 1.6 Momentum | e-Consult
1.6 Momentum (1 questions)
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Given:
- Mass (m) = 0.5 kg
- Initial velocity (vi) = 0 m/s
- Final velocity (vf) = 2.0 m/s
- Time (Δt) = 3.0 s
Impulse Equation: Impulse (J) = F Δt
Calculate the Force:
F = Δp / Δt, where Δp is the change in momentum.
Δp = m(vf - vi) = 0.5 kg * (2.0 m/s - 0 m/s) = 1.0 kg m/s
F = 1.0 kg m/s / 3.0 s = 0.33 N (approximately)
Impulse Equation: Impulse (J) = F Δt
Calculation:
J = 0.33 N × 3.0 s = 0.99 Ns (approximately)
Change in Momentum:
Δp = m(vf - vi) = 0.5 kg * (2.0 m/s - 0 m/s) = 1.0 kg m/s
Answer: The impulse delivered to the ball is approximately 0.99 Ns. The change in momentum of the ball is 1.0 kg m/s.