Chemistry – Organic chemistry - Formulae, functional groups and terminology | e-Consult
Organic chemistry - Formulae, functional groups and terminology (1 questions)
Three chemical tests to distinguish between a carboxylic acid and an alcohol are:
- Reaction with Sodium Bicarbonate (NaHCO3): A carboxylic acid reacts with sodium bicarbonate to produce carbon dioxide gas.
Chemical Principle: Carboxylic acids contain the -COOH group. The hydrogen atom of the -COOH group is acidic and can donate a proton (H+) to the bicarbonate ion (HCO3-). This forms carbonic acid (H2CO3), which is unstable and decomposes into carbon dioxide (CO2), water (H2O), and bicarbonate (HCO3-). The evolution of CO2 is a positive test for a carboxylic acid.
- Reaction with Sodium Metal (Na): Carboxylic acids react with sodium metal to produce hydrogen gas.
Chemical Principle: Carboxylic acids contain a hydrogen atom bonded to an oxygen atom in the -COOH group. This hydrogen atom can be abstracted by sodium, forming hydrogen gas (H2) and a carboxylate ion. This reaction is a positive test for a carboxylic acid.
- Reaction with an ester in the presence of a catalyst (e.g., dilute acid): A carboxylic acid can be esterified with an alcohol in the presence of an acid catalyst. This reaction is readily reversible.
Chemical Principle: The reaction is an equilibrium process. The presence of an ester (a product of the reaction) shifts the equilibrium towards the reactants (carboxylic acid and alcohol), indicating the presence of a carboxylic acid. This is a positive test for a carboxylic acid.