Published by Patrick Mutisya · 14 days ago
Know that an object in an elliptical orbit travels faster when it is closer to the Sun and explain this behaviour using the principle of conservation of energy.
\$U = -\frac{G M_{\odot} m}{r}\$
where \$G\$ is the universal gravitational constant.
\$K = \frac12 m v^{2}\$
with \$v\$ the orbital speed.
\$E = K + U = \frac12 m v^{2} - \frac{G M_{\odot} m}{r}\$
For a given orbit \$E\$ is constant (conserved).
When the object moves from aphelion to perihelion the distance \$r\$ decreases. Because the potential energy term \$-\frac{G M_{\odot} m}{r}\$ becomes more negative, the total energy \$E\$ must stay the same. To compensate, the kinetic energy \$K\$ must increase, which means the speed \$v\$ must increase.
Mathematically, setting the total energy at aphelion (\$ra\$, \$va\$) equal to that at perihelion (\$rp\$, \$vp\$):
\$\$\frac12 m va^{2} - \frac{G M{\odot} m}{r_a}
= \frac12 m vp^{2} - \frac{G M{\odot} m}{r_p}\$\$
Rearranging gives the relationship between speeds:
\$vp^{2} = va^{2} + 2 G M{\odot}\!\left(\frac{1}{rp}-\frac{1}{r_a}\right)\$
Since \$rp < ra\$, the term in parentheses is positive, so \$vp > va\$.
| Parameter | Aphelion | Perihelion |
|---|---|---|
| Distance from Sun, \$r\$ (km) | 152.1 × 10⁶ | 147.1 × 10⁶ |
| Orbital speed, \$v\$ (km s⁻¹) | 29.29 | 30.29 |
Even a modest change in distance produces a noticeable change in speed, illustrating the principle.