Published by Patrick Mutisya · 14 days ago
State that (electron) antineutrinos are produced during β⁻ decay and (electron) neutrinos are produced during β⁺ decay.
Beta decay is a type of radioactive decay in which a nucleus changes its proton–neutron composition by emitting a beta particle (an electron or a positron) together with a (anti)neutrino. The two main modes are:
In β⁻ decay a neutron inside the nucleus converts into a proton, emitting an electron (e⁻) and an electron antineutrino ( \$\bar{\nu}_e\$ ). The reaction can be written as
\$n \;\rightarrow\; p + e^- + \bar{\nu}_e\$
At the nuclear level this is expressed as
\$\;^{A}{Z}\!X \;\rightarrow\; ^{A}{Z+1}\!Y + e^- + \bar{\nu}_e\$
Key points:
In β⁺ decay a proton inside the nucleus converts into a neutron, emitting a positron (e⁺) and an electron neutrino ( \$\nu_e\$ ). The reaction is
\$p \;\rightarrow\; n + e^+ + \nu_e\$
At the nuclear level:
\$\;^{A}{Z}\!X \;\rightarrow\; ^{A}{Z-1}\!Y + e^+ + \nu_e\$
Key points:
| Feature | β⁻ Decay | β⁺ Decay |
|---|---|---|
| Change in nucleus | n → p (Z + 1) | p → n (Z − 1) |
| Emitted particle | Electron (e⁻) | Positron (e⁺) |
| Associated (anti)neutrino | Electron antineutrino ( \$\bar{\nu}_e\$ ) | Electron neutrino ( \$\nu_e\$ ) |
| Lepton number balance | e⁻ (+1) + \$\bar{\nu}_e\$ (−1) = 0 | e⁺ (−1) + \$\nu_e\$ (+1) = 0 |
| Typical energy release | \overline{0}.5–3 MeV (shared between e⁻ and \$\bar{\nu}_e\$) | \overline{1}.022 MeV + kinetic energy (positron mass‑energy must be supplied) |
The (anti)neutrino ensures that the following conservation laws are satisfied in beta decay:
During β⁻ decay an electron antineutrino ( \$\bar{\nu}e\$ ) is emitted together with the electron, whereas during β⁺ decay an electron neutrino ( \$\nue\$ ) is emitted together with the positron.