Sketch and explain the current-voltage graphs for a resistor of constant resistance, a filament lamp and a diode
Topic 4.2.4 – Resistance
Learning objectives
Define electrical resistance and state its unit.
State the quantitative relationship R = V ⁄ I and explain how it follows from Ohm’s law.
Describe how the resistance of a uniform conductor depends on its length, cross‑sectional area and material (R ∝ L, R ∝ 1⁄A, ρ).
Carry out a simple volt‑ammeter experiment to determine the resistance of an unknown resistor and interpret the resulting V‑I graph.
Sketch and explain the current‑voltage (I‑V) graphs for:
a resistor of constant resistance,
a filament lamp,
a semiconductor diode.
Core concepts
Concept
Expression / Explanation
Resistance
R = V ⁄ I (Ω = V ⁄ A)
Ohm’s law (for an ohmic conductor)
V = IR → I ∝ V (linear relationship)
Dependence on dimensions
R = ρ L ⁄ A where ρ is the resistivity (Ω·m), L is length (m) and A is cross‑sectional area (m²). Thus R ∝ L and R ∝ 1⁄A.
Practical method – determining an unknown resistance
Connect the unknown resistor in series with a variable DC source, an ammeter (to measure I) and a voltmeter (to measure V across the resistor).
Vary the source voltage and record several (V, I) pairs.
Plot the points on a graph with V (V) on the horizontal axis and I (A) on the vertical axis.
If the resistor is ohmic the points lie on a straight line through the origin; the slope of the line is 1⁄R. Hence R = ΔV ⁄ ΔI.
1. Resistor of constant resistance (ohmic resistor)
An ideal metallic resistor obeys Ohm’s law over the range of voltages used in the IGCSE exam.
Quantity
Symbol
Relationship
Resistance
R
Constant (ohmic)
Current
I
I = V⁄R
Graphical features
Horizontal axis: Voltage, V (V)
Vertical axis: Current, I (A)
The line passes through the origin because I = 0 when V = 0.
Slope = ΔI⁄ΔV = 1⁄R. A steeper slope indicates a lower resistance.
Ideal I‑V graph for a constant‑R resistor – straight line through the origin.
2. Filament lamp (non‑ohmic conductor)
A filament lamp is made of a metal (usually tungsten) whose resistance increases markedly as the filament temperature rises.
Temperature (approx.)
Effect on resistance
Room temperature (≈ 20 °C)
Low resistance (e.g. 10 Ω for a small lamp)
Operating temperature (≈ 2500 °C)
Resistance can be 40–60 times larger (≈ 500 Ω for the same lamp)
Why the I‑V curve bends
At low voltage the filament is cool → small R → the initial part of the curve is almost linear.
Increasing V raises the current, which heats the filament; R rises, so the incremental increase in I for a given increase in V becomes smaller.
The result is a convex‑upward curve that flattens as V (and temperature) increase.
Typical experimental procedure
Connect the lamp to a variable DC source with an ammeter in series and a voltmeter across the lamp.
Record V and I for several settings, then plot I versus V.
The plotted points start at the origin and curve upward, never forming a straight line.
Typical I‑V curve for a filament lamp – convex upward due to temperature‑dependent resistance.
3. Semiconductor diode
A diode conducts readily in the forward direction but blocks current in reverse bias (apart from a tiny leakage current). Its I‑V characteristic has three distinct regions.
Region
Bias
Current behaviour
Typical voltage
A
Reverse bias
Very small leakage (≈ µA or less)
0 → –V_R (breakdown not shown)
B
Forward bias, below knee
Almost zero – diode “off”
0 → V_k (≈ 0.6 V for Si, 0.3 V for Ge)
C
Forward bias, above knee
Current rises rapidly (exponential)
V > V_k
Graphical features
Axes: V (V) horizontal, I (A) vertical.
Region A: a near‑horizontal line close to the I = 0 axis (reverse‑bias leakage).
Region B: a shallow, almost flat segment up to the “knee” voltage V_k.
Region C: a steep upward curve. In IGCSE sketches this is often drawn as a straight line with a very steep slope, but the true relation is exponential:
\(I = I_0\bigl(e^{qV/kT} - 1\bigr)\).
Mark V_k on the graph (≈ 0.6 V for a silicon diode).
Convex upward; slope decreases as V (and temperature) increase
Semiconductor diode
Very high R in reverse bias, very low R after turn‑on
Three‑region curve: flat reverse, knee, then steep forward rise (exponential)
Practical tips for sketching I‑V graphs
Label both axes clearly, including units (V (V) on the horizontal, I (A) on the vertical).
Start the graph at the origin for any device that carries zero current when the voltage is zero (resistor, filament lamp). For a diode the reverse‑bias line is drawn close to the I = 0 axis, not at the origin.
For an ohmic resistor draw a straight line; the slope equals 1⁄R.
When resistance changes with temperature or voltage, indicate the curvature qualitatively – exact numerical values are not required at IGCSE level.
For the diode, clearly mark the knee voltage V_k and note the typical value (≈ 0.6 V for silicon).
Common misconceptions
“A filament lamp has a constant resistance.” In reality the filament’s resistance can increase 40–60 times as it heats.
“The diode’s forward characteristic is a straight line.” The current rises exponentially; the straight‑line sketch is only a shorthand for “very steep”.
“A reverse‑biased diode conducts a normal current.” Only a tiny leakage current flows until breakdown, which is outside the IGCSE syllabus.
“Current can flow from cathode to anode.” In forward bias current flows from anode to cathode only.
Exam checklist
State the definition of resistance (R = V ⁄ I) and its unit.
Explain how R depends on length, area and material (R ∝ L, R ∝ 1⁄A).
Describe the volt‑ammeter method for finding an unknown resistance and indicate how the slope of the V‑I graph gives R.
Draw a straight‑line I‑V graph for a constant‑R resistor, label the axes and write “slope = 1⁄R”.
Sketch the curved I‑V graph for a filament lamp and give a one‑sentence explanation (temperature‑dependent increase in R).
Produce the three‑region I‑V graph for a diode, label the reverse‑bias region, the knee voltage (≈ 0.6 V for Si) and the steep forward region.
For each component, provide a concise physical reason for the shape of its graph.
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