Published by Patrick Mutisya · 14 days ago
State the principle of conservation of momentum.
Linear momentum, denoted by \$\mathbf{p}\$, is a vector quantity defined for a particle of mass \$m\$ moving with velocity \$\mathbf{v}\$:
\$\mathbf{p}=m\mathbf{v}\$
The change in momentum of an object is equal to the impulse applied to it.
\$\Delta\mathbf{p} = \mathbf{J} = \int \mathbf{F}\,dt\$
For a constant force \$F\$ acting over a time interval \$\Delta t\$:
\$\Delta\mathbf{p}=F\Delta t\$
Statement: In an isolated system (i.e., a system on which no external net force acts), the total linear momentum remains constant.
\$\sum \mathbf{p}{\text{initial}} = \sum \mathbf{p}{\text{final}}\$
This principle follows directly from Newton’s second and third laws and is valid for any interaction, whether the bodies collide or separate.
| Collision Type | Momentum | Kinetic Energy | Typical Example |
|---|---|---|---|
| Elastic | Conserved | Conserved | Billiard balls striking each other |
| Inelastic | Conserved | Not conserved (some lost as deformation, heat, sound) | Car crash where vehicles stick together |
| Perfectly Inelastic | Conserved | Maximum loss of kinetic energy | Two clay balls sticking together after impact |
Problem: A 2.0 kg cart moving at \$3.0\ \text{m s}^{-1}\$ collides head‑on with a 3.0 kg cart initially at rest. After the collision the two carts stick together. Find their common speed immediately after the collision.
Solution:
\$m1 v{1i} + m2 v{2i} = (m1+m2)v_f\$
\$ (2.0)(3.0) + (3.0)(0) = (2.0+3.0)v_f \$
\$6.0 = 5.0 vf \quad\Rightarrow\quad vf = 1.2\ \text{m s}^{-1}\$
The combined system moves at \$1.2\ \text{m s}^{-1}\$ in the original direction of the 2.0 kg cart.