Published by Patrick Mutisya · 14 days ago
Know that, in general, sound travels faster in solids than in liquids and faster in liquids than in gases.
Sound is a longitudinal mechanical wave. Its speed depends on how quickly adjacent particles can transmit the disturbance. Two main material properties control this:
In general, solids are both stiffer and less compressible than liquids, while gases are the least stiff and most compressible. Consequently:
For a solid (where the relevant elastic modulus is Young’s modulus \$E\$):
\$v_{\text{solid}} = \sqrt{\frac{E}{\rho}}\$
For a fluid (liquid or gas) the bulk modulus \$K\$ is used:
\$v_{\text{fluid}} = \sqrt{\frac{K}{\rho}}\$
In an ideal gas the bulk modulus can be expressed as \$K = \gamma p\$, giving the familiar formula
\$v_{\text{gas}} = \sqrt{\frac{\gamma p}{\rho}} = \sqrt{\gamma R T}\$
where \$\gamma\$ is the ratio of specific heats, \$p\$ the pressure, \$R\$ the specific gas constant and \$T\$ the absolute temperature.
| Medium | Typical Speed of Sound | Reason for Speed |
|---|---|---|
| Steel (solid) | ≈ 5 000 m s⁻¹ | Very high Young’s modulus and moderate density |
| Water (liquid, 20 °C) | ≈ 1 480 m s⁻¹ | High bulk modulus, but higher density than solids |
| Air (gas, 20 °C, 1 atm) | ≈ 343 m s⁻¹ | Low bulk modulus and low density; speed increases with temperature |
Calculate the speed of sound in dry air at 25 °C. Use \$\gamma = 1.40\$, \$R = 287\ \text{J kg}^{-1}\text{K}^{-1}\$, and \$T = 298\ \text{K}\$.
\$v = \sqrt{\gamma R T} = \sqrt{1.40 \times 287 \times 298} \approx 346\ \text{m s}^{-1}\$
Because sound propagation requires both elasticity and inertia, the relative magnitudes of these properties in different states of matter dictate the speed:
Understanding these relationships helps explain everyday observations, such as why you hear a train whistle more clearly through the rails than through the air.