Published by Patrick Mutisya · 14 days ago
Explain that the random fusion of gametes at fertilisation produces genetically different individuals.
During metaphase I of meiosis, each homologous pair aligns independently of the others. The number of possible gamete chromosome combinations can be expressed as:
\$\text{Number of combinations} = 2^{n}\$
where n is the haploid chromosome number. For humans (n = 23):
\$2^{23} \approx 8.4 \times 10^{6} \text{ different gametes per individual}\$
During prophase I, homologous chromosomes exchange segments, creating new allele combinations on each chromosome. This further increases genetic diversity beyond that predicted by independent assortment alone.
When a sperm and an ovum fuse, the resulting zygote inherits a random combination of the parental chromosomes. The total number of possible zygotic genotypes is the product of the number of possible sperm and ovum genotypes.
\$\text{Possible zygotes} = (2^{n}){\text{sperm}} \times (2^{n}){\text{ovum}} = 2^{2n}\$
For humans this yields:
\$2^{46} \approx 7.0 \times 10^{13} \text{ possible genotypes}\$
Consider a species with a haploid number of 2 (chromosome pairs A/a and B/b). The possible gametes and resulting zygotes are shown below.
| Gamete from Parent 1 | Gamete from Parent 2 | Zygote Genotype |
|---|---|---|
| AB | AB | AABB |
| AB | Ab | AABb |
| AB | aB | AaBB |
| AB | ab | AaBb |
| Ab | AB | AABb |
| Ab | Ab | AAbb |
| Ab | aB | AaBb |
| Ab | ab | Aabb |
| aB | AB | AaBB |
| aB | Ab | AaBb |
| aB | aB | aaBB |
| aB | ab | aaBb |
| ab | AB | AaBb |
| ab | Ab | Aabb |
| ab | aB | aaBb |
| ab | ab | aabb |