If the angle of incidence in air is \$30^\circ\$, find the angle of refraction in water.
Apply Snell’s Law with \$n_{\text{air}} \approx 1.00\$:
\$\$
1.00 \sin 30^\circ = 1.33 \sin \theta_2 \\
\sin \theta_2 = \frac{0.5}{1.33} \approx 0.376 \\
\theta_2 = \sin^{-1}(0.376) \approx 22^\circ
\$\$
The ray bends towards the normal, as expected.
Common Misconceptions
Confusing refractive index with the angle of refraction – they are different quantities.
Assuming \$n\$ is always greater than 1; gases at low pressure can have \$n\$ very close to 1.
Thinking that light slows down permanently – the speed changes only while the light is in the medium.
Suggested diagram: Ray of light incident on a flat interface between air and water, showing incident angle \$\theta1\$, refracted angle \$\theta2\$, normal line, and labels for \$n{\text{air}}\$ and $n{\text{water}}.
Summary
The refractive index \$n\$ is the ratio of the speed of a wave in one medium to its speed in another.
Absolute refractive index: \$n = c/v\$.
Snell’s Law links refractive indices to the angles of incidence and refraction.
Higher \$n\$ means slower light in that medium and greater bending towards the normal.