understand that a photon is a quantum of electromagnetic energy

Published by Patrick Mutisya · 14 days ago

Energy and Momentum of a Photon – Cambridge A-Level Physics 9702

Energy and Momentum of a Photon

Learning Objective

Understand that a photon is a quantum of electromagnetic energy and be able to calculate its energy and momentum.

Key Concepts

  • Photon as a particle of light.
  • Quantisation of electromagnetic radiation.
  • Relationship between frequency, wavelength, energy and momentum.

Fundamental Relations

The energy \$E\$ of a photon is directly proportional to its frequency \$\nu\$:

\$E = h\nu\$

Using the speed of light \$c = \lambda \nu\$, the energy can also be expressed in terms of wavelength \$\lambda\$:

\$E = \frac{hc}{\lambda}\$

The momentum \$p\$ of a photon is related to its wavelength by:

\$p = \frac{h}{\lambda} = \frac{E}{c}\$

Constants

SymbolQuantityValue
\$h\$Planck constant\$6.626 \times 10^{-34}\ \text{J·s}\$
\$c\$Speed of light in vacuum\$2.998 \times 10^{8}\ \text{m·s}^{-1}\$
\$\lambda\$Wavelength of photonVariable
\$\nu\$Frequency of photonVariable

Derivation of Photon Momentum

  1. Start from the wave relation \$c = \lambda \nu\$.
  2. Combine with \$E = h\nu\$ to get \$E = hc/\lambda\$.
  3. Use the relativistic relation \$E^2 = (pc)^2 + (m0c^2)^2\$ with \$m0 = 0\$ for a photon, giving \$E = pc\$.
  4. Therefore \$p = E/c = h/\lambda\$.

Applications

  • Photoelectric effect – photons eject electrons from metal surfaces.
  • Radiation pressure – momentum transfer from light to surfaces.
  • Compton scattering – change in photon wavelength due to collision with electrons.

Example Problem

Problem: Calculate the energy and momentum of a photon with wavelength \$500\ \text{nm}\$ (green light).

Solution:

  1. Convert wavelength to metres: \$\lambda = 500\ \text{nm} = 5.00 \times 10^{-7}\ \text{m}\$.
  2. Energy:

    \$E = \frac{hc}{\lambda} = \frac{(6.626 \times 10^{-34})(2.998 \times 10^{8})}{5.00 \times 10^{-7}} \approx 3.98 \times 10^{-19}\ \text{J}\$

  3. Momentum:

    \$p = \frac{h}{\lambda} = \frac{6.626 \times 10^{-34}}{5.00 \times 10^{-7}} \approx 1.33 \times 10^{-27}\ \text{kg·m·s}^{-1}\$

Suggested Diagram

Suggested diagram: A photon represented as a wave packet traveling with wavelength \$\lambda\$, showing arrows for energy \$E = h\nu\$ and momentum \$p = h/\lambda\$.

Summary

A photon carries quantised energy \$E = h\nu\$ and momentum \$p = h/\lambda\$. These relationships link the wave and particle descriptions of light and underpin many phenomena in modern physics.