Published by Patrick Mutisya · 14 days ago
Understand that a photon is a quantum of electromagnetic energy and be able to calculate its energy and momentum.
The energy \$E\$ of a photon is directly proportional to its frequency \$\nu\$:
\$E = h\nu\$
Using the speed of light \$c = \lambda \nu\$, the energy can also be expressed in terms of wavelength \$\lambda\$:
\$E = \frac{hc}{\lambda}\$
The momentum \$p\$ of a photon is related to its wavelength by:
\$p = \frac{h}{\lambda} = \frac{E}{c}\$
| Symbol | Quantity | Value |
|---|---|---|
| \$h\$ | Planck constant | \$6.626 \times 10^{-34}\ \text{J·s}\$ |
| \$c\$ | Speed of light in vacuum | \$2.998 \times 10^{8}\ \text{m·s}^{-1}\$ |
| \$\lambda\$ | Wavelength of photon | Variable |
| \$\nu\$ | Frequency of photon | Variable |
Problem: Calculate the energy and momentum of a photon with wavelength \$500\ \text{nm}\$ (green light).
Solution:
\$E = \frac{hc}{\lambda} = \frac{(6.626 \times 10^{-34})(2.998 \times 10^{8})}{5.00 \times 10^{-7}} \approx 3.98 \times 10^{-19}\ \text{J}\$
\$p = \frac{h}{\lambda} = \frac{6.626 \times 10^{-34}}{5.00 \times 10^{-7}} \approx 1.33 \times 10^{-27}\ \text{kg·m·s}^{-1}\$
A photon carries quantised energy \$E = h\nu\$ and momentum \$p = h/\lambda\$. These relationships link the wave and particle descriptions of light and underpin many phenomena in modern physics.