\[
\Phi = B A \cos\theta
\]
where
\(B\) = magnetic field strength (T),
\(A\) = area of the loop (m²),
\(\theta\) = angle between the field direction and the normal to the surface.
The cosine term shows that the flux is maximum when the field is perpendicular to the loop (\(\theta =0^\circ\)) and zero when the field is parallel (\(\theta =90^\circ\)).
\[
\text{flux linkage}=N\Phi .
\]
\[
\mathcal{E}= -\,\frac{d(N\Phi)}{dt}= -N\frac{d\Phi}{dt}
\]
\(\mathcal{E}\) is the induced e.m.f. (V). The minus sign is the mathematical statement of Lenz’s law.
The negative sign ensures that the induced e.m.f. (and thus the induced current) produces a magnetic field whose effect is to *reduce* the original change in flux, i.e. it enforces the opposition described by Lenz’s law.
| Factor | Effect on \(\mathcal{E}\) (from \(\mathcal{E}= -N\,d\Phi/dt\)) | How to vary in the laboratory |
|---|---|---|
| Number of turns, \(N\) | \(\mathcal{E}\propto N\) | Wind more turns on the same core or swap to a coil with a different \(N\). |
| Magnetic field strength, \(B\) | \(\mathcal{E}\propto B\) | Use a stronger permanent magnet or an electromagnet with adjustable current. |
| Area of the loop, \(A\) | \(\mathcal{E}\propto A\) | Use larger coils or change the effective area with a sliding rod. |
| Angular (or linear) speed, \(\omega\) (or \(v\)) | \(\mathcal{E}\propto \omega\) (or \(v\)) | Vary motor speed, or drop the magnet faster. |
| Angle \(\theta\) between field and loop normal | \(\Phi = BA\cos\theta\); varying \(\theta\) changes \(\Phi\) sinusoidally, giving an alternating e.m.f. | Rotate the coil continuously (see generator experiment). |
| Resistance of the circuit, \(R\) | Does not affect \(\mathcal{E}\); however \(I = \mathcal{E}/R\) so the measured current changes. | Insert known resistors and measure the current with an ammeter. |
Consider a single‑turn rectangular coil of area \(A\) rotating at a constant angular speed \(\omega\) in a uniform magnetic field \(B\) (field direction perpendicular to the axis of rotation).
\[
\frac{d\Phi}{dt}= -BA\omega\sin(\omega t).
\]
\[
\mathcal{E}(t)= -N\frac{d\Phi}{dt}= NAB\omega\sin(\omega t).
\]
\[
\boxed{\mathcal{E}_{\max}=NAB\omega }.
\]
| Experiment | Purpose | Apparatus | Key Procedure | Observations & Interpretation |
|---|---|---|---|---|
| Moving Magnet Through a Coil | Show that a *changing* magnetic flux induces an e.m.f. | Coil (~100 turns), galvanometer, bar magnet, stand. |
|
|
| Rotating Coil in a Uniform Magnetic Field (Generator) | Quantify how \(N\), \(A\), \(B\) and \(\omega\) affect \(\mathcal{E}\). | Square coil (adjustable \(N\) and \(A\)), wooden frame, horseshoe magnet, variable‑speed motor, voltmeter. |
|
|
| Falling Magnet Through a Conducting Ring (Lenz’s‑law demonstration) | Show that the induced e.m.f. creates a magnetic field that opposes the motion that produced it. | Copper ring, strong neodymium magnet, vertical stand, stop‑watch (or electronic timer). |
|
|
| Current‑Carrying Loop Near a Magnet (Opposition to change) | Demonstrate the direction of the magnetic force on a current‑carrying coil. | Rectangular coil on a low‑friction air track, fixed bar magnet, DC power supply, ammeter. |
|
|
\[
\mathcal{E}(t)=NAB\omega\sin\omega t
\]
Hand‑crank generators and large power‑station alternators operate on this principle.
\[
\mathcal{E}p = -Np\frac{d\Phi}{dt},\qquad
\mathcal{E}s = -Ns\frac{d\Phi}{dt}
\]
Hence the voltage ratio is
\[
\boxed{\frac{Vs}{Vp}= \frac{Ns}{Np}}
\]
(ideal transformer, neglecting losses).
Problem: A coil of \(N=200\) turns, each turn having an area \(A=0.015\;\text{m}^2\), rotates at \(\omega = 50\;\text{rad s}^{-1}\) in a uniform magnetic field of \(B=0.25\;\text{T}\). Find the maximum induced e.m.f.
Solution:
\[
\mathcal{E}_{\max}=NAB\omega
= (200)(0.015\;\text{m}^2)(0.25\;\text{T})(50\;\text{rad s}^{-1})
= 37.5\;\text{V}.
\]
The coil will therefore produce a sinusoidal e.m.f. of amplitude 37.5 V, i.e. \(\mathcal{E}(t)=37.5\sin(50t)\) V.
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