Use simple constructions, measurements and calculations for reflection by plane mirrors

Published by Patrick Mutisya · 14 days ago

Cambridge IGCSE Physics 0625 – 3.2.1 Reflection of Light

3.2.1 Reflection of Light

Objective

Use simple constructions, measurements and calculations to investigate reflection by plane mirrors.

Key Concepts

  • The incident ray, reflected ray and the normal are all in the same plane.
  • Law of Reflection: the angle of incidence equals the angle of reflection (\$\thetai = \thetar\$).
  • A plane mirror produces a virtual image that is upright, laterally inverted and the same distance behind the mirror as the object is in front of it.

Ray Diagram Construction

  1. Draw the mirror as a straight line and mark a point on the line as the point of incidence.
  2. Draw the normal at the point of incidence (a line perpendicular to the mirror).
  3. From the object, draw the incident ray to the point of incidence.
  4. Measure the angle between the incident ray and the normal (\$\theta_i\$).
  5. From the point of incidence, draw the reflected ray on the opposite side of the normal such that \$\thetar = \thetai\$.
  6. Extend the reflected ray backward (dotted line) to locate the virtual image.

Suggested diagram: Ray diagram for a plane mirror showing incident ray, normal, reflected ray and virtual image.

Measurements

When performing an experiment with a plane mirror, record the following quantities for each trial:

TrialObject distance, \$d_o\$ (cm)Angle of incidence, \$\theta_i\$ (°)Angle of reflection, \$\theta_r\$ (°)Image distance, \$d_i\$ (cm)
1
2
3

Calculations

For a plane mirror the relationship between object and image distances is:

\$di = -do\$

The negative sign indicates that the image is virtual and located behind the mirror.

To verify the law of reflection, calculate the difference between the measured angles:

\$\Delta\theta = |\thetai - \thetar|\$

A small \$\Delta\theta\$ (typically < 1°) confirms the law.

Example Problem

Given: An object is placed 30 cm in front of a plane mirror. The incident ray makes an angle of \$35^\circ\$ with the normal.

Find:

  1. The angle of reflection.
  2. The position of the image relative to the mirror.

Solution:

  1. By the law of reflection, \$\thetar = \thetai = 35^\circ\$.
  2. The image distance is \$di = -do = -30\text{ cm}\$. The image is 30 cm behind the mirror, directly opposite the object.

Common Errors and How to Avoid Them

  • Measuring angles from the mirror surface instead of the normal. Always draw and use the normal as the reference line.
  • Confusing virtual and real images. A virtual image cannot be projected onto a screen; it appears behind the mirror.
  • Incorrect sign convention for distances. Use a negative sign for image distances in plane mirror calculations.

Summary

  • The incident ray, reflected ray and normal lie in the same plane.
  • Law of reflection: \$\thetai = \thetar\$.
  • Plane mirrors produce upright, laterally inverted virtual images at the same distance behind the mirror as the object is in front.
  • Accurate construction of ray diagrams and careful measurement of angles verify the law of reflection.

Practice Questions

  1. A student shines a laser beam at a plane mirror such that the incident angle is \$20^\circ\$. What is the angle of reflection?
  2. An object is 45 cm in front of a plane mirror. Where is the image formed? State its nature (real/virtual, upright/inverted).
  3. During an experiment, the measured angles are \$\thetai = 40^\circ\$ and \$\thetar = 42^\circ\$. Calculate \$\Delta\theta\$ and comment on the result.
  4. Explain why a plane mirror does not change the size of the image, using the geometry of the ray diagram.