Published by Patrick Mutisya · 14 days ago
Define the Hubble constant \$H0\$ as the ratio of the speed at which a galaxy is moving away from the Earth to its distance from the Earth; recall and use the equation \$H0 = \frac{v}{d}\$.
Observations of distant galaxies show that their spectral lines are shifted towards longer wavelengths. The shift is quantified by the red‑shift \$z\$, where
\$\$
z = \frac{\Delta \lambda}{\lambda_0}
\$\$
For speeds much less than the speed of light, the recession velocity \$v\$ can be approximated by
\$\$
v \approx cz
\$\$
where \$c = 3.00 \times 10^5\ \text{km s}^{-1}\$ is the speed of light. Hubble’s empirical law states that \$v\$ is directly proportional to the distance \$d\$ of the galaxy from the observer:
\$\$
v = H_0 d
\$\$
Re‑arranging gives the definition of the Hubble constant:
\$\$
H_0 = \frac{v}{d}
\$\$
Galaxy A has a measured red‑shift \$z = 0.005\$. Its distance, determined from Cepheid variables, is \$d = 20\ \text{Mpc}\$. Find the recession velocity and the value of \$H_0\$ implied by this galaxy.
\$\$
v = cz = (3.00 \times 10^5\ \text{km s}^{-1})(0.005) = 1.5 \times 10^3\ \text{km s}^{-1}
\$\$
\$\$
H_0 = \frac{1.5 \times 10^3\ \text{km s}^{-1}}{20\ \text{Mpc}} = 75\ \text{km s}^{-1}\text{Mpc}^{-1}
\$\$
The result is close to the accepted range of \$70 \pm 5\ \text{km s}^{-1}\text{Mpc}^{-1}\$, showing good agreement.
| Method | Measured \$H_0\$ (km s⁻¹ Mpc⁻¹) | Notes |
|---|---|---|
| Type Ia Supernovae | 73 ± 2 | Standard candle method |
| Cosmic Microwave Background (Planck) | 67.4 ± 0.5 | Model‑dependent |
| Cepheid \cdot ariables | 71 ± 3 | Local distance ladder |
The Hubble constant \$H0\$ quantifies the rate of expansion of the Universe. It is defined by the simple ratio \$H0 = v/d\$, where \$v\$ is the recession speed of a galaxy and \$d\$ its distance from Earth. Accurate determination of \$H_0\$ is central to cosmology, linking observations of distant objects to the age and size of the Universe.