Describe an experiment to determine the position of the centre of gravity of an irregularly shaped plane lamina

Published by Patrick Mutisya · 14 days ago

Cambridge IGCSE Physics 0625 – Centre of Gravity

1.5.3 Centre of Gravity

Learning Objective

Describe an experiment to determine the position of the centre of gravity of an irregularly shaped plane lamina.

Key Concepts

The centre of gravity (CG) of a thin, flat object is the point through which the resultant weight of the object acts. For a uniform lamina the CG coincides with the centre of mass.

Mathematically, if the lamina is divided into small elements of mass \$mi\$ at positions \$(xi, yi)\$, the coordinates of the centre of gravity \$(xG, y_G)\$ are given by

\$xG = \frac{\sum mi xi}{\sum mi}, \qquad yG = \frac{\sum mi yi}{\sum mi}\$

In practice we locate \$G\$ by using the principle that a lamina will balance when supported at its centre of gravity.

Apparatus

ItemPurpose
Irregularly shaped thin lamina (e.g., cardboard cut‑out)Object whose CG is to be found
Two thin, straight supports (e.g., metal rods or wooden strips)Provide a line of support for the lamina
Adjustable mounting board or benchHolds the supports in a fixed relative position
Plumb line (string with a small weight)Indicates the vertical direction (gravity)
Ruler or measuring scaleMeasure distances on the lamina
Paper and pencilRecord measurements and draw construction lines

Experimental Principle

When a lamina is supported at two points, it will balance if the line joining the support points passes through the centre of gravity. By locating two such lines (using different pairs of support points) the intersection of the lines gives the position of \$G\$.

Procedure

  1. Place the mounting board on a stable surface and fix the two thin supports so that they are parallel and spaced about 10 cm apart.
  2. Lay the irregular lamina on the supports so that it can rotate freely.
  3. Gently adjust the lamina until it is in static equilibrium (it does not tip to either side). At this position the line joining the two support points passes through \$G\$.
  4. Mark the points where the lamina contacts each support. Using a ruler, draw a straight line on the lamina joining these two contact points. Label this line as \$L_1\$.
  5. Rotate the lamina (or reposition the supports) to a new orientation and repeat steps 2–4 to obtain a second line \$L_2\$ that also passes through \$G\$.
  6. Using a pencil, extend \$L1\$ and \$L2\$ until they intersect. The intersection point is the centre of gravity \$G\$ of the lamina.
  7. Measure the coordinates of \$G\$ relative to a chosen reference corner of the lamina (e.g., the lower‑left corner). Record the distances \$xG\$ and \$yG\$.

Data Recording Table

TrialSupport points (A, B) – coordinates (cm)Line drawn \$L_i\$Intersection point \$G\$ (cm)
1(x₁, y₁) , (x₂, y₂)Line \$L_1\$To be determined after both trials
2(x₃, y₃) , (x₄, y₄)Line \$L_2\$

Analysis

Because each line \$L_i\$ is forced to pass through the centre of gravity, the intersection of any two such lines must be \$G\$. No calculations are required beyond measuring the intersection point, but you may verify the result by checking that the lamina balances when supported at \$G\$.

Safety and Precautions

  • Ensure the mounting board is stable to prevent the lamina from falling.
  • Handle the plumb line carefully; the weight should be small enough not to damage the lamina.
  • Do not force the lamina into equilibrium; allow it to settle naturally.

Extension Questions

  • How would the method change if the lamina were not uniform (i.e., its density varied across the surface)?
  • Explain why the centre of gravity of a symmetric shape (e.g., a rectangle) lies at its geometric centre.
  • Discuss sources of experimental error in this method and how they could be minimised.

Suggested diagram: A top‑view sketch showing the irregular lamina on two supports, the two balance lines \$L1\$ and \$L2\$, and their intersection point \$G\$.