Published by Patrick Mutisya · 14 days ago
Investigate the progress of enzyme‑catalysed reactions by:
Enzymes are biological catalysts that speed up reactions by lowering the activation energy (\$E_a\$). They bind substrates at the active site, forming an enzyme–substrate complex (ES) which then converts to product(s) and regenerates the free enzyme.
| Term | Definition |
|---|---|
| Active site | Specific region of the enzyme where substrate binds. |
| Enzyme–substrate complex (ES) | Transient complex formed during the catalytic cycle. |
| Turnover number (k_cat) | Number of substrate molecules converted per enzyme molecule per unit time. |
| Michaelis constant (K_m) | Substrate concentration at which the reaction rate is half of \$V_{max}\$. |
The instantaneous rate of an enzyme‑catalysed reaction can be expressed as:
\$\$
v = \frac{d[P]}{dt} = \frac{V{max}[S]}{Km + [S]}
\$\$
where \$[P]\$ is product concentration, \$[S]\$ is substrate concentration, \$V{max}\$ is the maximum rate, and \$Km\$ is the Michaelis constant.
Catalase catalyses the decomposition of hydrogen peroxide (\$\mathrm{H2O2}\$) into water and oxygen:
\$\$
2\,\mathrm{H2O2} \xrightarrow{\text{catalase}} 2\,\mathrm{H2O} + \mathrm{O2}\uparrow
\$\$
| Item | Purpose |
|---|---|
| Test tubes (10 mL) | Reaction vessels |
| Stopwatch | Timing the reaction |
| Gas syringe or graduated cylinder (inverted) | Collecting evolved \$\mathrm{O_2}\$ |
| Fresh potato or liver homogenate | Source of catalase |
| Hydrogen peroxide solution (3 % w/v) | Substrate |
| Thermostatic water bath | Maintain constant temperature |
| Time (s) | Volume of \$\mathrm{O_2}\$ (mL) |
|---|---|
| 0 | 0 |
| 10 | 0.8 |
| 20 | 1.5 |
| 30 | 2.1 |
| … | … |
Rate of product formation (\$v\$) can be obtained from the slope of the volume‑vs‑time graph:
\$\$
v = \frac{\Delta V{\mathrm{O2}}}{\Delta t}
\$\$
Convert volume to moles using the ideal gas equation (\$PV = nRT\$) if required.
Amylase hydrolyses starch into maltose and glucose:
\$\$
\text{Starch} + \text{H}_2\text{O} \xrightarrow{\text{amylase}} \text{Maltose} + \text{Glucose}
\$\$
| Item | Purpose |
|---|---|
| Test tubes (10 mL) | Reaction vessels |
| Stopwatch | Timing the reaction |
| Iodine solution (0.1 % w/v) | Detect residual starch (blue‑black colour) |
| Spectrophotometer (optional) | Measure absorbance at 620 nm for quantitative analysis |
| Saliva or pancreatic extract | Source of amylase |
| Starch solution (1 % w/v) | Substrate |
| Thermostatic water bath | Control temperature |
| Time (s) | Absorbance at 620 nm (A) |
|---|---|
| 0 | 0.85 |
| 30 | 0.62 |
| 60 | 0.38 |
| 90 | 0.12 |
| 120 | 0.02 |
Convert absorbance to concentration of starch using Beer‑Lambert law:
\$\$
A = \varepsilon \, l \, [\text{Starch}]
\$\$
Rate of substrate disappearance (\$v_{-S}\$) is then:
\$\$
v_{-S} = -\frac{\Delta [\text{Starch}]}{\Delta t}
\$\$
Enzyme kinetics can be explored by measuring either the appearance of product (catalase) or the disappearance of substrate (amylase). Both approaches rely on accurate, time‑resolved data collection and allow calculation of reaction rates, \$V{max}\$, and \$Km\$. Understanding how temperature and pH affect these rates provides insight into enzyme structure–function relationships, a key component of the Cambridge A‑Level Biology curriculum.