understand that the magnetic field due to the current in a solenoid is increased by a ferrous core

Published by Patrick Mutisya · 14 days ago

Magnetic Fields Due to Currents

Objective

Understand that the magnetic field inside a solenoid is increased when a ferrous core is inserted, and be able to calculate the resulting field.

1. Magnetic Field of a Long Solenoid

A long solenoid of length \(l\), carrying a current \(I\) through \(N\) turns, produces a magnetic field approximately uniform inside:

  • Number of turns per unit length: \(n = \dfrac{N}{l}\)
  • Field without core: \(B = \mu_0 n I\)

where \(\mu_0 = 4\pi\times10^{-7}\,\text{H/m}\) is the permeability of free space.

2. Effect of a Ferrous Core

When a core of relative permeability \(\mu_r\) is inserted, the magnetic field becomes

\[

B{\text{core}} = \mu0 \mu_r n I

\]

The core increases the field by a factor of \(\mur\). Typical ferrous materials have \(\mur\) ranging from 100 to 10,000.

3. Magnetic Permeability

The absolute permeability of the core is

\[

\mu = \mu0 \mur

\]

For a linear material, \(\mur\) is constant. In practice, \(\mur\) decreases with increasing magnetic field strength due to saturation.

4. Example Calculation

Calculate the magnetic field inside a solenoid of length \(0.5\,\text{m}\), with \(2000\) turns, carrying a current of \(2\,\text{A}\). The solenoid is filled with a core of relative permeability \(\mu_r = 500\).

  1. Compute \(n = \dfrac{2000}{0.5} = 4000\,\text{turns/m}\).
  2. Compute \(B{\text{core}} = \mu0 \mu_r n I = (4\pi\times10^{-7})(500)(4000)(2)\).
  3. Evaluate: \(B_{\text{core}} \approx 0.0050\,\text{T}\) (5 mT).
  4. For comparison, without the core: \(B = \mu_0 n I \approx 0.00001\,\text{T}\) (10 µT).

Thus the core increases the field by a factor of 500.

5. Summary Table

ParameterSymbolExpressionUnits
Number of turns per unit lengthn\(\dfrac{N}{l}\)turns m\(^{-1}\)
Magnetic field (air core)B\(\mu_0 n I\)T
Magnetic field (ferrous core)Bcore\(\mu0 \mur n I\)T
Absolute permeability\(\mu\)\(\mu0 \mur\)H m\(^{-1}\)

6. Practice Questions

  1. For a solenoid with \(N = 1500\) turns, \(l = 0.3\,\text{m}\), and \(I = 3\,\text{A}\), calculate the magnetic field inside the solenoid when:

    1. It has an air core.
    2. It contains a core with \(\mu_r = 200\).

  2. Explain qualitatively why the magnetic field increases when a ferrous core is inserted.
  3. Describe what happens to the magnetic field as the core material approaches magnetic saturation.

7. Suggested Diagram

Suggested diagram: A long solenoid with a ferrous core inserted, indicating the direction of the magnetic field lines inside the core.