Cambridge IGCSE Physics 0625 – 1.2 Motion
Objective
Recall and use the equation for average speed: the total distance travelled divided by the total time taken.
Key Concepts
- Distance is a scalar quantity measured in metres (m).
- Time is a scalar quantity measured in seconds (s).
- Average speed is a scalar quantity expressed in metres per second (m s−1).
- The equation applies to any motion where the total distance and total time are known, regardless of changes in speed during the journey.
Equation
The average speed is given by:
\$v_{\text{avg}} = \dfrac{D}{t}\$
where D is the total distance travelled and t is the total time taken.
Step‑by‑Step Procedure
- Identify the total distance D travelled. Ensure the unit is metres.
- Identify the total time t taken. Ensure the unit is seconds.
- Insert the values into the equation \$v_{\text{avg}} = \dfrac{D}{t}\$.
- Perform the division to obtain the average speed.
- Check the units: metres ÷ seconds = metres per second (m s−1).
Examples
| Example | Distance D (m) | Time t (s) | Average Speed vavg (m s−1) |
|---|
| 1 | 120 | 30 | \$\dfrac{120}{30} = 4\$ |
| 2 | 250 | 50 | \$\dfrac{250}{50} = 5\$ |
| 3 | 360 | 90 | \$\dfrac{360}{90} = 4\$ |
Practice Problems
- A cyclist travels a total distance of 180 m in 45 s. Calculate the average speed.
- A bus covers 500 m in 125 s. What is its average speed?
- A train travels 720 m in 180 s. Determine the average speed.
- Solution:
- \$v_{\text{avg}} = \dfrac{180}{45} = 4\$ m s−1
- \$v_{\text{avg}} = \dfrac{500}{125} = 4\$ m s−1
- \$v_{\text{avg}} = \dfrac{720}{180} = 4\$ m s−1
Suggested Diagram
Suggested diagram: A car traveling along a straight road covering distance D in time t.