Describe the formation of poly(ethene) as an example of addition polymerisation using ethene monomers

Organic Chemistry – Polymers

Objective

Describe the formation of poly(ethene) as an example of addition polymerisation using ethene monomers. 🧪

What is Poly(ethene)?

Poly(ethene), also known as polyethylene, is a long chain polymer made from the monomer ethene (C₂H₄). It is the most common plastic used in everyday items like bags, bottles and toys. 📚

Addition Polymerisation

In addition polymerisation, the double bond of each monomer is opened and the monomers link together to form a chain. No atoms are lost from the monomers. The general reaction is:

\$\ce{CH2=CH2} \xrightarrow{\text{radical initiator}} \ce{[-CH2-CH2-]_{n}}\$

  • Initiation: A radical initiator (e.g., peroxide) creates a reactive radical.
  • Propagation: The radical adds to the double bond of ethene, forming a new radical that continues adding more monomers.
  • Termination: Two growing chains combine or a chain reacts with a hydrogen atom, ending the growth.

Step‑by‑Step Mechanism

StepWhat HappensIllustration (LaTeX)
1. InitiationPeroxide breaks to give two radicals.\$\ce{RO-OR} \rightarrow 2\ce{RO.}\$
2. PropagationRadical adds to ethene, opening the double bond.\$\ce{RO. + CH2=CH2 \rightarrow RO-CH2-CH2.}\$
3. TerminationTwo radicals combine or a radical abstracts H.\$\ce{RO-CH2-CH2. + .CH2-CH2-OR \rightarrow RO-CH2-CH2-CH2-CH2-OR}\$

Analogy & Example

Think of each ethene monomer as a LEGO block with a double‑bond “connector”. When a radical initiator (the “magnet”) pulls the connector open, the blocks snap together one after another, forming a long chain. The chain grows until the magnet stops pulling or two chains snap together. This is like building a long train of cars that keeps adding cars until the engine stops.

Example: Making a plastic bag. Thousands of ethene molecules link together to give a flexible, strong material that can hold liquids.

Exam Tips

  1. Remember the three stages: Initiation, Propagation, Termination.
  2. Use the keyword “addition” to recall that no atoms are lost.
  3. Draw the double bond opening and show the radical site.
  4. Practice writing the overall reaction with the correct stoichiometry: \$\ce{n CH2=CH2 \rightarrow [-CH2-CH2-]_{n}}\$.
  5. Check that you label the initiator, propagating radical, and termination step.