Objective: Understand how the reflection of pulses of ultrasound at boundaries between tissues can be used to obtain diagnostic information about internal structures.
Ultrasound is sound with frequencies above the human hearing range (>20 kHz). Think of it as a super‑fast “ping” that can travel through the body and bounce back from different tissues.
The speed of sound in soft tissue is about 1540 m s⁻¹. The wave travels until it reaches a boundary where the acoustic impedance changes.
Acoustic impedance is defined as \$Z = \rho c\$, where \$\rho\$ is density and \$c\$ is sound speed.
The fraction of the wave that is reflected is given by the reflection coefficient:
\$R = \left(\frac{Z2 - Z1}{Z2 + Z1}\right)^2\$
A large difference in impedance (e.g., bone vs. muscle) gives a strong echo, while similar impedances give weak echoes.
The time delay between transmission and reception tells us how far the boundary is:
\$d = \frac{v\,t}{2}\$
The factor ½ accounts for the wave travelling to the boundary and back again.
| Tissue | Density (kg m⁻³) | Speed of sound (m s⁻¹) | Impedance (Rayl) |
|---|---|---|---|
| Water | 1000 | 1480 | 1.48 × 10⁶ |
| Muscle | 1040 | 1580 | 1.65 × 10⁶ |
| Bone | 1900 | 4080 | 7.75 × 10⁶ |
Imagine shouting in a canyon. The sound travels, hits a cliff, and echoes back. The louder the echo, the steeper the cliff. In the body, a bone is like a steep cliff – it reflects a strong echo, while a soft organ is a gentle slope – it reflects a faint echo.
Remember:
Tip: When given a time delay, first double the distance travelled (to the boundary and back) before dividing by the speed.
Answer guide:
Ultrasound imaging relies on the physics of sound waves: production, propagation, reflection, and time‑of‑flight. By mastering these concepts, you’ll be able to interpret ultrasound images and answer exam questions with confidence.