When light hits a smooth surface, it bounces back. The law of reflection states that the angle of incidence (\$\thetai\$) is equal to the angle of reflection (\$\thetar\$).
\$\displaystyle \thetai = \thetar\$
Both angles are measured from the normal (an imaginary line perpendicular to the surface).
| Incident Ray | Normal | Reflected Ray |
|---|---|---|
| ↗️ | ⬇️ | ↘️ |
| \$\theta_i\$ | \$\theta_r\$ |
A ray of light strikes a mirror at an angle of \$30^\circ\$ to the normal. What is the angle of the reflected ray?
Answer: \$30^\circ\$ (since \$\thetai = \thetar\$).
If a ray is incident at \$45^\circ\$ to the surface (not the normal), what is the angle of incidence and reflection?
First, find angle to normal: \$90^\circ - 45^\circ = 45^\circ\$. Therefore, \$\thetai = \thetar = 45^\circ\$.
A light ray hits a polished metal surface at \$10^\circ\$ to the normal. Sketch the path and label the angles.
Draw the incident ray, the normal, and the reflected ray, labeling both angles as \$10^\circ\$.