Define the empirical formula of a compound as the simplest whole‑number ratio of atoms or ions in a compound. 🔬
Think of a recipe that uses the fewest ingredients while still giving you the same dish. The empirical formula is like that recipe – it tells you the smallest whole‑number ratio of atoms that makes up the compound. 🧪
Example: Water (\$H2O\$) is already in its simplest ratio \$2:1\$, so its empirical formula is \$H2O\$. But consider glucose, \$C6H{12}O6\$. The smallest whole‑number ratio is \$1:2:1\$, so its empirical formula is \$CH2O\$.
| Element | % (approx.) | Moles (g/mol) | Ratio |
|---|---|---|---|
| C | 40.0 | 0.667 | 1 |
| H | 14.0 | 0.233 | 0.35 |
| O | 46.0 | 0.667 | 1 |
After dividing by the smallest mole (0.233) we get ratios: C = 2.86, H = 1, O = 2.86. Multiply by 3 to get whole numbers: C₈H₃O₈ → empirical formula \$CH_2O\$ (simplified).
Always check that the ratio you obtain is in the simplest whole‑number form. If you get fractions, multiply all ratios by the smallest integer that makes them whole numbers.
Imagine each atom as a Lego block. The empirical formula is the smallest set of blocks that can be assembled to build the entire structure. If you have 6 red blocks and 12 blue blocks, you can reduce them to 1 red and 2 blue blocks – that’s the empirical formula. 🧩
What is the empirical formula of the compound with the following percent composition?
Answer: \$CH_2O\$ (after calculation). 📐