A photon is a tiny packet of light energy that travels at the speed of light, c = 3 × 10⁸ m/s. Think of it like a miniature “light bullet” that can move through space without any mass, but still carries energy and can push on objects when it hits them. ✨
The energy of a photon is related to its frequency (ν) or wavelength (λ) by Planck’s equation:
\$E = h\nu = \dfrac{hc}{\lambda}\$
Where h is Planck’s constant (6.626 × 10⁻³⁴ J·s). If you know the wavelength, you can find the energy, and vice‑versa. 📐
Even though a photon has no mass, it still carries momentum. Imagine a tiny snowball (the photon) rolling into a wall; the wall feels a small push. The momentum p of a photon is given by:
\$p = \dfrac{E}{c}\$
Because E = hc/λ, we can also write:
\$p = \dfrac{h}{\lambda}\$
So the shorter the wavelength, the larger the momentum. 🌈
\$p = \dfrac{h}{\lambda} = \dfrac{6.626\times10^{-34}\,\text{J·s}}{5.00\times10^{-7}\,\text{m}} \approx 1.33\times10^{-27}\,\text{kg·m/s}\$
| Quantity | Symbol | Formula | Units |
|---|---|---|---|
| Energy | \$E\$ | \$E = \dfrac{hc}{\lambda}\$ | Joules (J) |
| Momentum | \$p\$ | \$p = \dfrac{E}{c} = \dfrac{h}{\lambda}\$ | kg·m/s |
| Frequency | \$\nu\$ | \$E = h\nu\$ | Hz |
Question: A photon has a wavelength of 400 nm. What is its momentum?
Answer: \$p = \dfrac{h}{\lambda} = \dfrac{6.626\times10^{-34}}{4.00\times10^{-7}} \approx 1.66\times10^{-27}\,\text{kg·m/s}\$.