Explain sacrificial protection in terms of the reactivity series and in terms of electron loss

Metals – Corrosion of Metals

Corrosion is the slow, natural process where a metal reacts with its environment (usually oxygen and water) and loses its shiny, protective surface. Imagine a superhero losing their powers when exposed to the wrong element – that’s what happens to metals when they corrode.

Sacrificial Protection – What Is It?

🛡️ Sacrificial protection is like having a brave sidekick that takes the hit instead of the main hero. A metal that is higher in the reactivity series (more reactive) is attached to the metal that needs protection. The sidekick metal (the sacrificial anode) corrodes first, sparing the protected metal.

Think of it as a “donor” metal giving up its electrons to protect a “receiver” metal, just like a friend giving up their lunch to keep you from getting hungry.

Reactivity Series Explanation

The reactivity series ranks metals from most reactive (top) to least reactive (bottom). In sacrificial protection, the metal placed on the left (more reactive) acts as the sacrificial anode.

Most ReactiveLess Reactive
ZnAl
FeCu
PbAu

In practice, a zinc anode is often attached to a steel pipe. The zinc corrodes (oxidises) first, protecting the steel.

Electron Loss Explanation

Corrosion is a redox reaction. The metal (anode) loses electrons:

\$M \rightarrow M^{n+} + ne^-\$

The electrons travel through the metal to the cathode, where they reduce oxygen:

\$O2 + 4H^+ + 4e^- \rightarrow 2H2O\$

In sacrificial protection, the sacrificial metal (e.g., Zn) has a more negative standard electrode potential (\$E^\circ\$) than the protected metal. Therefore, it prefers to lose electrons:

\$E^\circ_{\text{Zn/Zn}^{2+}} = -0.76\,\text{V}\$

while the protected metal (e.g., Fe) has a less negative potential:

\$E^\circ_{\text{Fe/Fe}^{2+}} = -0.44\,\text{V}\$

Because Zn is more reactive, it corrodes first, keeping Fe intact.

Exam Tips

  • Remember the reactivity series – the metal higher up is the sacrificial anode.
  • Use the equation: anode: metal → metalⁿ⁺ + ne⁻ and cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O.
  • When asked “Why does sacrificial protection work?”, answer: “Because the sacrificial metal has a more negative electrode potential, so it loses electrons first, protecting the other metal.”
  • Include a diagram of a simple sacrificial anode setup (you can draw it with text or describe it).
  • Use the emoji ⚡️ to highlight key points in your notes.