Recall and use in calculations the following facts:
Think of a water pipe that splits into two smaller pipes. The amount of water that flows into the junction must equal the total amount that flows out.
Mathematically:
\$I{\text{in}} = I{\text{out}}\$
In a parallel circuit with two branches:
\$I{\text{total}} = I1 + I_2\$
Example: If a 12 V battery supplies 3 A into a junction, and one branch carries 1.5 A, the other branch must carry 1.5 A.
Imagine a chain of dominoes. The total height of the chain is the sum of the heights of each domino.
For a series circuit:
\$V{\text{total}} = V1 + V2 + \dots + Vn\$
Example calculation:
| Component | Voltage (V) |
|---|---|
| Resistor 1 | 4 V |
| Resistor 2 | 6 V |
| Total | 10 V |
Think of a group of friends standing on a seesaw. Each friend experiences the same height relative to the ground, regardless of how many friends are on each side.
In a parallel arrangement:
\$V{\text{across each branch}} = V{\text{across the whole arrangement}}\$
Example: Two resistors, \$R1 = 4\,\Omega\$ and \$R2 = 6\,\Omega\$, are connected in parallel across a 12 V supply. Both branches see 12 V.
Current through each branch can be found using Ohm’s law:
\$I1 = \dfrac{V}{R1} = \dfrac{12}{4} = 3\,\text{A}\$
\$I2 = \dfrac{V}{R2} = \dfrac{12}{6} = 2\,\text{A}\$
Check with current conservation: \$I{\text{total}} = I1 + I_2 = 5\,\text{A}\$.