Exam Tip: Remember that the area under a velocity–time graph always gives you the displacement (not distance). Keep track of the sign of the area: positive area → forward, negative area → backward.
A velocity–time graph shows how an object's speed (and direction) changes over time.
The vertical axis is velocity v (m/s) and the horizontal axis is time t (s).
Think of it like a road map where the height of the line tells you how fast you’re going at each moment.
The key rule:
\$\text{Displacement } s = \int v(t)\,dt\$
In a graph, this integral is simply the area between the curve and the time axis.
• If the curve lies above the axis, the area is positive (forward motion).
• If it lies below, the area is negative (backward motion).
Analogy: Imagine a water tank. The area is the amount of water that flows in (positive) or out (negative) over time.
A car starts from rest, accelerates at a constant rate of 2 m/s² for 5 s, then travels at a constant speed of 10 m/s for 8 s, and finally stops over 4 s.
Sketch the velocity–time graph and find the total displacement.
| Segment | Description | Area (m) |
|---|---|---|
| 1 | Acceleration from 0 to 10 m/s (triangle) | ½ × 5 s × 10 m/s = 25 m |
| 2 | Constant speed 10 m/s for 8 s (rectangle) | 10 m/s × 8 s = 80 m |
| 3 | Deceleration from 10 m/s to 0 (triangle, negative) | -½ × 4 s × 10 m/s = -20 m |
| Total Displacement | 25 m + 80 m – 20 m = 85 m | |
The car travels a total of 85 m forward. Notice how the negative area from the deceleration segment reduces the total.
Quick Review:
• Area = displacement
• Positive area → forward, negative area → backward
• Break the graph into simple shapes, calculate each area, sum with signs
• Keep units consistent and double‑check signs