Use decay equations, using nuclide notation, to show the emission of α-particles, β-particles and γ-radiation

5.2.3 Radioactive Decay ⚛️

What is Radioactive Decay?

Imagine a busy train station where some trains (atoms) are unstable and decide to change their form. They do this by throwing off particles or energy to become more stable. This process is called radioactive decay and is written with nuclide notation:

Nuclide notation shows the element, its mass number (A), and its atomic number (Z). For example, \$^{226}\text{Ra}\$ means radium with 226 nucleons (protons + neutrons) and 88 protons.

Alpha Decay (α)

Think of an alpha particle as a tiny, heavy “ball” that the nucleus throws out. It’s actually a helium nucleus: 2 protons + 2 neutrons.

Decay equation example:

\$^{226}\text{Ra} \;\xrightarrow{\;\alpha\;}\; ^{222}\text{Rn} + \alpha\$

  • Mass number decreases by 4 (226 → 222).
  • Atomic number decreases by 2 (88 → 86).
  • Result: radon‑222, a gas that can be found in old houses.

Beta Decay (β)

Beta decay is like a “switch” inside the nucleus: a neutron turns into a proton, emitting an electron (β⁻) or a positron (β⁺).

Two common types:

  1. β⁻ (neutron → proton + electron + antineutrino)
  2. β⁺ (proton → neutron + positron + neutrino)

Example (β⁻):

\$^{14}\text{C} \;\xrightarrow{\;\beta^-\;}\; ^{14}\text{N} + \beta^- + \bar{\nu}_e\$

Example (β⁺):

\$^{11}\text{C} \;\xrightarrow{\;\beta^+\;}\; ^{11}\text{B} + \beta^+ + \nu_e\$

Notice how the mass number stays the same but the atomic number changes by ±1.

Gamma Radiation (γ)

Gamma rays are like the “after‑party” of the nucleus: a highly excited nucleus releases excess energy as a high‑energy photon.

Decay equation (no change in A or Z):

\$^{60}\text{Co}^* \;\xrightarrow{\;\gamma\;}\; ^{60}\text{Co}\$

Because it’s just energy, gamma decay is often accompanied by α or β decay.

Common Decay Chains (Table)

Parent NuclideDecay ModeDaughter Nuclide
\$^{238}\text{U}\$α\$^{234}\text{Th}\$
\$^{234}\text{Th}\$α\$^{230}\text{Pa}\$
\$^{230}\text{Pa}\$β⁻\$^{230}\text{U}\$

Each step follows the same rules: A changes by 4 for α, stays same for β, and stays same for γ. Z changes by ±2 for α, ±1 for β, and stays same for γ.

Exam Tips 📚

  • Remember the rules: α → ΔA = –4, ΔZ = –2; β⁻ → ΔA = 0, ΔZ = +1; β⁺ → ΔA = 0, ΔZ = –1; γ → ΔA = 0, ΔZ = 0.
  • Use the nuclide notation: Write the parent, the decay arrow with the particle symbol, and the daughter.
  • Check mass numbers first: They give you a quick way to spot mistakes.
  • Practice with real isotopes: Try writing the decay of \$^{137}\text{Cs}\$ or \$^{241}\text{Am}\$.
  • Explain the process: In written answers, describe why the nucleus emits a particle (to become more stable).