⚛️ Particles (atoms/molecules) are always moving.
• In solids they vibrate in fixed spots.
• In liquids they slide past one another.
• In gases they rush around freely, colliding with the walls of their container.
Temperature is a measure of the average kinetic energy of the particles.
When \$T\$ rises, particles move faster → more frequent & stronger collisions with the walls → the gas pushes harder against the container → the volume \$V\$ increases (if the pressure \$P\$ is kept constant).
Analogy: Imagine a crowded dance floor. If everyone starts dancing faster (higher \$T\$), they bump into the walls more often, so the dance floor feels more crowded and expands if it can.
Mathematically: \$V \propto T \quad (P \text{ constant})\$
Pressure is the force exerted per unit area by the gas particles hitting the walls.
When \$P\$ increases (by squeezing the container), the particles are forced into a smaller space → the volume \$V\$ decreases (if the temperature \$T\$ is kept constant).
Analogy: Think of a balloon filled with air. Squeezing the balloon pushes the air molecules closer together, so the balloon shrinks.
Mathematically: \$V \propto \frac{1}{P} \quad (T \text{ constant})\$
The Ideal Gas Law links all three variables:
\$PV = nRT\$
Keep \$n\$ constant:
• Increase \$T\$ → \$V\$ increases (if \$P\$ constant).
• Increase \$P\$ → \$V\$ decreases (if \$T\$ constant).
• Changing both \$T\$ and \$P\$ simultaneously requires solving the equation.
📏 A sample of 2.0 mol of an ideal gas occupies 22.4 L at 1.00 atm and 273 K.
What will be the new volume if the temperature is raised to 546 K while keeping the pressure constant?
Answer: \$V_2 = 44.8\$ L.
| Variable | Effect on Volume (others constant) |
|---|---|
| Temperature (\$T\$) | \$V\$ increases (if \$P\$ constant) |
| Pressure (\$P\$) | \$V\$ decreases (if \$T\$ constant) |
| Number of moles (\$n\$) | \$V\$ increases (if \$P\$ and \$T\$ constant) |