Describe and explain how the relative molecular mass of a gas influences its rate of diffusion.
Exam Tip: Remember Graham’s Law:
\$\frac{Rate1}{Rate2} = \sqrt{\frac{M2}{M1}}\$
where \(M\) is the molar mass. Use it to compare rates quickly.
Diffusion is the spontaneous spread of particles from an area of high concentration to an area of low concentration. Think of a drop of food colouring in water – it spreads out until the colour is evenly distributed.
Gases with lighter molecules move faster because they have higher average kinetic energy at a given temperature. The faster they move, the quicker they spread out.
Graham’s Law shows the relationship:
Imagine two balloons racing on a windy day:
Balloon A zips ahead because it’s lighter and can move faster through the air. The same principle applies to gas molecules.
Compare hydrogen (H₂, M = 2 g mol⁻¹) and oxygen (O₂, M = 32 g mol⁻¹) at the same temperature:
| Gas | Molar Mass (g mol⁻¹) | Relative Rate (H₂ : O₂) |
|---|---|---|
| H₂ | 2 | 1 : 0.25 |
| O₂ | 32 | 0.25 : 1 |
Hydrogen diffuses about four times faster than oxygen.
Exam Tip: When given two gases, calculate the ratio of their rates using the square root of the inverse molar masses. Example:
\$\frac{Rate{CH4}}{Rate{CO2}} = \sqrt{\frac{M{CO2}}{M{CH4}}}\$
Plug in \(M{CH4}=16\) and \(M{CO2}=44\) to find the ratio.
Which gas will diffuse fastest at room temperature? (Hint: think of the lightest gas you can name.)
Answer: Hydrogen (H₂) – it has the lowest molar mass.