Use the relationship amount of substance $(mathrm{mol})=frac{ ext { mass }(mathrm{g})}{ ext { molar mass } (mathrm{g} / mathrm{mol})}$

Stoichiometry – The Mole and the Avogadro Constant 🧪

What is a mole? 🔬

Think of a mole as a super‑big bag of marbles. Just as a bag might hold 12 marbles, a mole always holds exactly

\$6.022 \times 10^{23}\$ entities (atoms, molecules, ions, etc.). This number is called the Avogadro constant and is the same for every substance.

Molar Mass – The Weight of One Mole 📏

The molar mass is the mass of one mole of a substance. It is measured in grams per mole (g mol⁻¹). For example, the molar mass of water (H₂O) is:

\$M_{\ce{H2O}} = 2(1.008) + 15.999 \approx 18.015\ \text{g mol}^{-1}\$

The Core Formula – From Mass to Moles ➡️

The relationship between mass, molar mass and amount of substance is:

\$n = \frac{m}{M}\$

where:

  • \$n\$ = number of moles (mol)
  • \$m\$ = mass of the sample (g)
  • \$M\$ = molar mass (g mol⁻¹)

Step‑by‑Step Example 🚀

How many moles of sodium chloride (NaCl) are in 58.44 g?

  1. Find the molar mass of NaCl:

    • \$M_{\ce{Na}} = 22.99\$ g mol⁻¹
    • \$M_{\ce{Cl}} = 35.45\$ g mol⁻¹
    • \$M_{\ce{NaCl}} = 22.99 + 35.45 = 58.44\$ g mol⁻¹

  2. Apply the formula:

    \$n = \frac{m}{M} = \frac{58.44\ \text{g}}{58.44\ \text{g mol}^{-1}} = 1.00\ \text{mol}\$

  3. Interpretation: 58.44 g of NaCl contains exactly one mole of NaCl, i.e., \$6.022 \times 10^{23}\$ NaCl formula units.

From Moles to Atoms – Using Avogadro's Number 🔢

To find the number of atoms or molecules:

\$N = n \times N_A\$

where \$N_A = 6.022 \times 10^{23}\ \text{mol}^{-1}\$.

Example: How many atoms of carbon are in 2.00 g of CO₂?

  1. Find \$M_{\ce{CO2}} = 12.01 + 2(15.999) = 44.01\$ g mol⁻¹.
  2. Calculate moles of CO₂:

    \$n = \frac{2.00}{44.01} = 0.0455\ \text{mol}\$

  3. Each CO₂ molecule contains 1 carbon atom, so:

    \$N_{\ce{C}} = 0.0455\ \text{mol} \times 6.022 \times 10^{23}\ \text{mol}^{-1} \approx 2.74 \times 10^{22}\ \text{atoms}\$

Exam Tips & Tricks 📚

  • Always check units – the answer must be in moles, grams, or number of entities as required.
  • Use the exact molar mass from the periodic table (not rounded) to avoid cumulative errors.
  • Remember that \$N_A\$ is a constant – you can use \$6.02 \times 10^{23}\$ for quick estimates.
  • When converting between mass and moles, keep the equation \$n = m/M\$ in mind; it’s the “backbone” of stoichiometry.
  • Practice with real‑world examples (e.g., fuel consumption, battery capacity) to see how moles appear outside the lab.

Quick Reference Table 📊

QuantitySymbolUnits
Amount of substance\$n\$mol
Mass\$m\$g
Molar mass\$M\$g mol⁻¹
Avogadro constant\$N_A\$mol⁻¹