Define ultrasound as sound with a frequency higher than 20 kHz

3.4 Sound

Objective

Define ultrasound as sound with a frequency higher than \$20\,\text{kHz}\$.

What is Sound?

Sound is a mechanical wave that travels through a medium (air, water, solids) by the vibration of particles. When you clap your hands, the air molecules vibrate and create a wave that reaches your ears, letting you hear the sound. 🎧

Frequency and Pitch

The frequency of a sound wave determines its pitch. Higher frequency = higher pitch; lower frequency = lower pitch. Frequency is measured in hertz (Hz).

RangeFrequency (Hz)Common Example
Low20–2000Bass drum, human voice
Mid2000–20000Guitar, piano
High20000–40000Bird chirps, high‑pitched alarms
Ultrasound\$>20\,\text{kHz}\$Medical imaging, cleaning, dog whistles

Ultrasound

Ultrasound is sound with a frequency higher than \$20\,\text{kHz}\$. Because humans cannot hear it, we use it in many practical ways:

  • Medical ultrasound imaging: waves bounce off tissues to create pictures of the inside of the body. 🩺
  • Cleaning: high‑frequency vibrations dislodge dirt from jewellery or surgical instruments. 🧼
  • Animal communication: some animals (e.g., bats, dolphins) use ultrasound for echolocation. 🦇🐬
  • Industrial testing: detecting cracks in metal by sending ultrasound waves through it. 🛠️

Analogies & Everyday Examples

  • Echo in a canyon – The time it takes for sound to return tells you how far away the wall is.
  • Dog whistles – Dogs hear the high‑frequency sound, but we don’t. Think of it as a secret language.
  • Ultrasound in a kitchen – The high‑frequency vibrations that clean your dishes are like invisible waves that shake off grime.

Exam Tips

  1. Remember the key definition: Ultrasound = sound with \$f > 20\,\text{kHz}\$.
  2. Use the frequency ranges table to quickly answer questions about pitch.
  3. When asked about uses of ultrasound, list at least two and give a short example.
  4. Draw a simple diagram of a sound wave and label frequency and wavelength.
  5. Practice converting between frequency and wavelength using \$c = f \lambda\$ (speed of sound in air ≈ \$340\,\text{m/s}\$).