Centripetal acceleration is the acceleration that keeps an object moving in a circular path. It always points toward the centre of the circle, just like how a car turns around a roundabout and feels pushed toward the middle.
It is given by two equivalent formulas:
Here, \$r\$ is the radius of the circle, \$\omega\$ is the angular velocity in radians per second, and \$v\$ is the linear speed in metres per second.
When you see a problem with a rotating object, first decide whether you have angular or linear data. Use the appropriate formula:
Check units: \$r\$ in metres, \$\omega\$ in rad s⁻¹, \$v\$ in m s⁻¹. The result will be in m s⁻².
Imagine a child on a merry‑go‑round. As the ride spins, the child feels a force pushing them toward the centre. That feeling is due to centripetal acceleration. The faster the ride spins (higher \$\omega\$), the stronger the push.
A car is moving in a circle of radius \$r = 20\,\text{m}\$ at a constant speed of \$v = 10\,\text{m s}^{-1}\$. Calculate the centripetal acceleration.
Solution:
Use \$a = \dfrac{v^2}{r}\$:
\$a = \dfrac{(10\,\text{m s}^{-1})^2}{20\,\text{m}} = \dfrac{100}{20} = 5\,\text{m s}^{-2}\$
So the car experiences a centripetal acceleration of \$5\,\text{m s}^{-2}\$ toward the centre.
| Formula | When to Use |
|---|---|
| \$a = r \omega^2\$ | You have angular velocity \$\omega\$. |
| \$a = \dfrac{v^2}{r}\$ | You have linear speed \$v\$. |
Remember: \$a = r \omega^2 = \dfrac{v^2}{r}\$. Pick the formula that matches the data you have.