Describe how paper chromatography is used to separate mixtures of soluble coloured substances, using a suitable solvent

Paper Chromatography: Separating Colours 🎨

What is Paper Chromatography?

Paper chromatography is a simple, low‑cost technique that separates a mixture of soluble coloured substances on a strip of paper. Think of it as a colour‑sorting game where each colour moves at its own pace, revealing the hidden components of a mixture.

Analogy: Imagine you have a bag of mixed marbles (the mixture). If you slide the bag across a smooth floor (the paper) while a gentle breeze (the solvent) pushes it, the lighter marbles will travel further than the heavier ones. Paper chromatography works on a similar principle, but with molecules instead of marbles.

Materials & Setup

  • Whatman paper or any thin, white filter paper
  • Solvent (mobile phase) – e.g., a mixture of water, ethanol, and acetone (common for coloured inks)
  • Glass or plastic tray (to hold the solvent)
  • Capillary tube or a small dropper
  • Marker or pencil for drawing a baseline
  • Ruler (to measure distances)
  • Safety goggles and gloves (always wear protective gear!)

Procedure

  1. Draw a horizontal line 1–2 cm from the bottom of the paper using a pencil.
  2. Using a capillary tube, apply a tiny spot of the mixture (≈ 0.5 mm) on the line.
  3. Place the paper in the tray so that the spot is above the solvent level (do not let the spot touch the solvent).
  4. Cover the tray to prevent evaporation and let the solvent rise by capillary action.
  5. When the solvent front has travelled about 8–10 cm, remove the paper and let it dry.
  6. Measure the distance from the baseline to each coloured spot and to the solvent front.
  7. Calculate the Rf value for each spot:



    Formula: \$R_f = \frac{distance\; travelled\; by\; solute}{distance\; travelled\; by\; solvent}\$



    Example: If a spot travelled 4 cm and the solvent front travelled 10 cm, \$R_f = \frac{4}{10} = 0.40\$.

Theory Behind Separation

In paper chromatography, the separation is governed by two competing processes:

  • Adsorption – molecules stick to the paper (which is mainly cellulose). Molecules that bind strongly move slowly.
  • Solubility in the solvent – molecules that dissolve well in the solvent travel faster.

Each component of the mixture has a unique balance of these two properties, giving it a distinct Rf value. The higher the Rf, the more soluble the component in the solvent and the less adsorbed on the paper.

Example: Separating Ink Components

Suppose you have a pen ink that contains three coloured dyes: blue, red, and yellow. After running paper chromatography:

DyeRf Value
Blue0.65
Red0.45
Yellow0.30

Here, blue travels farthest because it is most soluble in the solvent, while yellow stays closest to the baseline due to stronger adsorption.

Exam Tips for IGCSE Chemistry 0620

Remember:

  • Define mobile phase (solvent) and stationary phase (paper).
  • Explain the Rf value and how it is calculated.
  • Use the analogy of marbles to illustrate the balance between adsorption and solubility.
  • Show a simple diagram (drawn with a pencil) of the paper, solvent front, and spots.
  • Include a table of Rf values for the components you studied.
  • Answer the question: “Why does a component with a higher Rf value appear farther from the baseline?” – because it is more soluble in the solvent.

Use clear, concise language and label all parts of your diagram. Good luck! 🍀