A stationary wave is a wave pattern that does not travel through a medium. Instead, it stays in one place, with points that oscillate in place called nodes (zero displacement) and points that oscillate with maximum amplitude called antinodes (maximum displacement).
Imagine a string fixed at both ends, like a guitar string. When you pluck it, a wave travels to the right. At the same time, a wave travels to the left from the other end. When these two waves meet, they superimpose. The resulting displacement at any point \(x\) and time \(t\) is the sum of the two travelling waves:
\$y(x,t)=A\sin(kx-\omega t)+A\sin(kx+\omega t)\$
Using the trigonometric identity for the sum of sines, this simplifies to:
\$y(x,t)=2A\sin(kx)\cos(\omega t)\$
Notice that the spatial part \$\sin(kx)\$ and the temporal part \$\cos(\omega t)\$ are separated. The spatial part determines where the nodes and antinodes are, while the temporal part tells us how the amplitude at those points changes over time.
The nodes occur where the sine term is zero:
\$\sin(kx)=0 \;\;\Rightarrow\;\; kx = n\pi \;\;\Rightarrow\;\; x = n\frac{\pi}{k} = n\frac{\lambda}{2}\$
So nodes are spaced by half a wavelength \$\lambda/2\$. Antinodes occur where the sine term is ±1:
\$\sin(kx)=\pm1 \;\;\Rightarrow\;\; kx = \frac{\pi}{2} + n\pi \;\;\Rightarrow\;\; x = \left(n+\tfrac12\right)\frac{\lambda}{2}\$
Thus antinodes are halfway between nodes.
Repeating this at different times shows that the nodes stay fixed while the antinodes oscillate in place.
For a guitar string of length \$L\$ fixed at both ends, the allowed standing wave patterns are:
| Mode (n) | Wavelength \$\lambda\$ | Frequency \$f\$ |
|---|---|---|
| 1 | \$2L\$ | \$\frac{v}{2L}\$ |
| 2 | \$L\$ | \$\frac{v}{L}\$ |
| 3 | \$2L/3\$ | \$\frac{3v}{2L}\$ |
Each mode has \$n\$ nodes (including the fixed ends) and \$n-1\$ antinodes.