Exam Tip: In a series circuit, the total resistance is simply the sum of all individual resistances. Remember the formula: \$R{\text{total}} = R1 + R2 + \dots + Rn\$.
Think of a series circuit like a single water pipe that splits into several smaller pipes one after another. The water (current) must pass through each pipe (resistor) in turn, so the total resistance is the sum of all the individual resistances.
In a parallel circuit, imagine a main road that splits into several side roads. The current can choose any path, so the overall resistance is lower than any single branch. The formula for two resistors in parallel is:
\$R{\text{total}} = \dfrac{R1 R2}{R1 + R_2}\$
\$R{\text{total}} = \sum{i=1}^{n} R_i\$
Calculate the total resistance of the following series circuit:
| Resistor | Value (Ω) |
|---|---|
| \$R_1\$ | 4 |
| \$R_2\$ | 6 |
| \$R_3\$ | 10 |
Solution:
\$R_{\text{total}} = 4\,\Omega + 6\,\Omega + 10\,\Omega = 20\,\Omega\$
Exam Tip: When you see a series circuit diagram, look for a single path that the current follows. Count the resistors and add their values. Quick mental math: 4 + 6 = 10, then 10 + 10 = 20. Keep your answer in ohms (Ω). 🚀