Describe the transfer of charge during electrolysis, covering:
Think of the external circuit like a river that carries water (electrons) from the negative terminal (source) to the positive terminal (load). The electrons flow through the wire because the electric field pushes them, just as gravity pulls water downstream.
In electrolysis, the power supply (battery or DC source) forces electrons to move:
Because electrons are tiny, we can’t see them, but their flow is what powers the chemical changes.
At each electrode, electrons either leave (oxidation) or arrive (reduction). This is where the real chemistry happens.
\$\text{M}^{n+} + n\,e^- \rightarrow \text{M} \quad \text{(reduction)}\$
\$\text{M} \rightarrow \text{M}^{n+} + n\,e^- \quad \text{(oxidation)}\$
\$\text{M}^{n+} + n\,e^- \rightarrow \text{M}\$
Example: In a copper electrolysis cell with CuSO₄ solution, at the cathode we have:
\$\text{Cu}^{2+} + 2\,e^- \rightarrow \text{Cu (solid)}\$
At the anode (if it's a copper electrode) we have:
\$\text{Cu (solid)} \rightarrow \text{Cu}^{2+} + 2\,e^-\$
The electrolyte is like a traffic lane for ions. When electrons are added or removed at the electrodes, ions move to maintain charge balance.
In the copper cell example, the Cu²⁺ ions drift toward the cathode, while SO₄²⁻ anions drift toward the anode to keep the solution electrically neutral.
| Electrode | Reaction | Electron Flow |
|---|---|---|
| Cathode (−) | \$\text{Cu}^{2+} + 2\,e^- \rightarrow \text{Cu}\$ | Electrons enter the electrode from the external circuit. |
| Anode (+) | \$\text{Cu} \rightarrow \text{Cu}^{2+} + 2\,e^-\$ | Electrons leave the electrode to the external circuit. |
When answering questions about electrolysis:
Remember: The external circuit always carries electrons from the anode to the cathode.