Welcome to the world of the tiny! In this section we’ll explore how the nucleon number (total number of protons + neutrons) and the charge (number of protons) stay the same, even when atoms change during nuclear reactions. Think of it like a secret recipe that never changes, no matter how many times you cook it. 🍲
A nucleon is either a proton or a neutron. The nucleon number (A) is the sum of protons (Z) and neutrons (N). The charge is simply the number of protons, Z.
Analogy: Imagine a box of LEGO bricks. Each brick is a nucleon. The total number of bricks is A, while the number of red bricks (representing protons) is Z. The colour of the bricks (charge) never changes, even if you rearrange them.
| Reaction Type | Example | Check Conservation |
|---|---|---|
| Alpha Decay | \$^{226}\text{Ra} \rightarrow ^{222}\text{Rn} + ^{4}\text{He}\$ | A: 226 = 222 + 4; Z: 88 = 86 + 2 |
| Beta Minus Decay | \$^{14}\text{C} \rightarrow ^{14}\text{N} + e^- + \bar{\nu}_e\$ | A: 14 = 14; Z: 6 = 7 - 1 |
| Fusion (Proton-Proton Chain) | \$4p \rightarrow ^{4}\text{He} + 2e^+ + 2\nu_e + \gamma\$ | A: 4 = 4; Z: 4 = 2 + 2 |
Picture a playground where children (nucleons) can swap places but the total number of children and the number of red‑topped children (protons) never change. Even if a child runs off or a new child joins, the total count and colour count stay constant. This is exactly what happens in nuclear reactions – the “playground rules” (conservation laws) keep the system balanced. 🛝
1️⃣ Quick Conservation Check
• Write down A and Z for each side of the reaction. If they match, you’re good!
2️⃣ Energy Balance
• Remember that a mass defect (Δm) leads to energy release: \$E = \Delta m\,c^2\$
• In exam questions, you may be asked to calculate the energy released; use the mass difference in atomic mass units (u) and multiply by 931.5 MeV/u.
3️⃣ Common Mistakes
• Forgetting to include the emitted particle (e.g., the electron in β⁻ decay).
• Mixing up the charge of the emitted particle (α is +2, β⁻ is –1, β⁺ is +1).
4️⃣ Practice Problem
• Given the reaction \$^{235}\text{U} + n \rightarrow ^{141}\text{Ba} + ^{92}\text{Kr} + 3n\$, check conservation of A and Z.
• Answer: A: 235+1 = 141+92+3 = 236; Z: 92 = 56+36 = 92. ✔️