Think of an X‑ray tube as a tiny flashlight that shoots out high‑energy electrons. The process is:
The energy of the X‑ray photon is given by the equation \$E = eV\$, where \$V\$ is the accelerating voltage.
Because X‑rays can pass through soft tissues but are absorbed by denser structures, they give a clear picture of bones and organs. It’s like looking through a translucent window that shows the hidden skeleton inside.
In PET, a radioactive tracer that decays by \$\beta^+\$ (positron) emission is injected into the body. When the positron meets an electron, they annihilate, producing two 511 keV X‑ray photons that travel in opposite directions. PET scanners detect these photons to create a 3‑D image of metabolic activity.
🔬 Analogy: Imagine a flashlight that emits a pair of twin beams; when the beams hit each other, they create a bright flash that the scanner records.
| Isotope | Half‑life | Common Use |
|---|---|---|
| \$^{18}\mathrm{F}\$ | 110 min | \$^{18}\mathrm{F}\$‑FDG for cancer imaging |
| \$^{11}\mathrm{C}\$ | 20 min | Brain metabolism studies |
| \$^{13}\mathrm{N}\$ | 10 min | Heart blood flow |
| \$^{15}\mathrm{O}\$ | 2 min | Brain oxygenation |
When answering questions about PET, highlight that the tracer must undergo \$\beta^+\$ decay to emit a positron, which then annihilates with an electron to produce two 511 keV X‑ray photons detected by the scanner. This chain of events is the core of PET imaging.
📝 Tip: Write the sequence as a short diagram: Tracer → β⁺ decay → Positron + Electron → Annihilation → 2 × 511 keV X‑rays → PET detector.
Which of the following isotopes is NOT typically used in PET scans?
Answer: C. \$^{131}\mathrm{I}\$ (used in radio‑iodine therapy, not PET).