In a redox reaction, two substances exchange electrons. One loses electrons (oxidation) and the other gains them (reduction). Because electrons move from one atom to another, both processes happen at the same time – that’s why we call it a simultaneous process.
Think of a seesaw: if one side goes up, the other must go down. In chemistry, electrons are the “seesaw” that moves from one atom to another. If electrons are removed from one atom (oxidation), they must appear somewhere else (reduction). They cannot happen in isolation.
\$\ce{Zn(s) + CuSO4(aq) -> ZnSO4(aq) + Cu(s)}\$
• Zn loses two electrons: \$\ce{Zn -> Zn^{2+} + 2e^-}\$ (oxidation)
• Cu^{2+} gains those electrons: \$\ce{Cu^{2+} + 2e^- -> Cu}\$ (reduction)
| Reaction | Oxidation | Reduction |
|---|---|---|
| Rusting of iron | \$\ce{Fe -> Fe^{2+} + 2e^-}\$ | \$\ce{O2 + 4e^- -> 2O^{2-}}\$ |
| Combustion of methane | \$\ce{CH4 -> CO2 + 8e^-}\$ | \$\ce{O2 + 4e^- -> 2O^{2-}}\$ |
| Batteries (e.g., Alkaline) | \$\ce{Zn -> Zn^{2+} + 2e^-}\$ | \$\ce{Cu^{2+} + 2e^- -> Cu}\$ |
⚡ Question: In the reaction \$\ce{Fe + CuSO4 -> FeSO4 + Cu}\$, which species is oxidised and which is reduced?
Answer: Fe is oxidised (loses electrons) and Cu²⁺ is reduced (gains electrons).
Redox reactions are all about the transfer of electrons. Because electrons must move from one atom to another, oxidation and reduction always occur together. Remember the seesaw analogy – one side goes up, the other goes down!