derive, using the definitions of speed, frequency and wavelength, the wave equation v = f λ

Progressive Waves 🚂

What is a wave?

A wave is a disturbance that travels through a medium, carrying energy from one place to another without transporting matter. Think of a ripple spreading across a pond after you drop a stone 🌊, or the sound of a drum vibrating through the air 🎵.

Key Definitions 📐

QuantitySymbolDefinitionUnits
Speed of the wave\$v\$Distance travelled by the wave per unit timem s⁻¹
Frequency\$f\$Number of complete cycles per secondHz (s⁻¹)
Wavelength\$\lambda\$Distance between two successive points in phase (e.g., crest to crest)m

Deriving the Wave Equation 🧮

Let’s imagine a wave traveling along a string. In one second, the wave will have moved a certain distance – that’s the speed \$v\$. During that same second, the wave will have completed \$f\$ full cycles. Each cycle covers a distance equal to one wavelength \$\lambda\$. Therefore:

  1. Distance travelled in 1 s = speed × time = \$v \times 1\$ = \$v\$.
  2. Distance covered by one cycle = wavelength = \$\lambda\$.
  3. Number of cycles in 1 s = frequency = \$f\$.
  4. So, total distance travelled = (distance per cycle) × (number of cycles) = \$\lambda \times f\$.
  5. Equating the two expressions for distance: \$v = f \lambda\$.

In block form, the wave equation is:

\$v = f \lambda\$

Real‑World Analogy 🎡

Picture a train (the wave) moving along a straight track (the medium).

- The speed of the train is \$v\$.

- Each carriage represents one wavelength \$\lambda\$.

- The number of carriages that pass a fixed point every second is the frequency \$f\$.

If the train travels 100 m in one second and has 10 carriages, each carriage is 10 m long: \$v = 10 \times 10 = 100\$ m s⁻¹. That’s exactly the wave equation in action!

Quick Practice Problems ??

  1. A sound wave travels at 340 m s⁻¹ and has a frequency of 170 Hz. What is its wavelength?
  2. A water wave has a wavelength of 2 m and a frequency of 0.5 Hz. What is its speed?
  3. Explain why a higher frequency wave travels faster if the wavelength stays the same.

Answers:

1) \$\lambda = v/f = 340/170 = 2\$ m.

2) \$v = f\lambda = 0.5 \times 2 = 1\$ m s⁻¹.

3) Because \$v = f\lambda\$, if \$\lambda\$ is constant, increasing \$f\$ directly increases \$v\$.

Take‑away Summary 📌

- Speed \$v\$ tells us how fast a wave moves.

- Frequency \$f\$ counts how many cycles pass a point each second.

- Wavelength \$\lambda\$ measures the length of one cycle.

- The fundamental relationship is \$v = f \lambda\$, linking all three concepts.

Remember the train analogy: speed = (carriages per second) × (length of each carriage). That’s the heart of wave physics!