understand that objects moving against a resistive force may reach a terminal (constant) velocity

Momentum and Newton’s Laws of Motion

1. What is Momentum?

Momentum is a measure of how much motion an object has. It is the product of mass and velocity: \$p = m\,v\$.

Think of it as the “push” an object carries when it moves.

🌟 Analogy: Imagine a bowling ball rolling down a hallway. The heavier the ball or the faster it rolls, the more momentum it has, so it’s harder to stop.

2. Newton’s Laws of Motion

  1. First Law (Inertia): An object stays at rest or moves at constant speed unless a net external force acts on it. ⚖️
  2. Second Law (F = ma): The net force on an object equals its mass times its acceleration: \$F_{\text{net}} = m\,a\$. This links force, mass, and acceleration. 🚀
  3. Third Law (Action–Reaction): For every action, there is an equal and opposite reaction. If you push a wall, the wall pushes back on you with the same force. 🤝

3. Resistive Forces and Terminal Velocity

When an object moves through a fluid (air, water), it experiences a resistive (drag) force that grows with speed.

The drag force can be approximated by: \$F{\text{drag}} = \tfrac{1}{2}\,\rho\,C{\text{d}}\,A\,v^{2}\$,

where \$\rho\$ is fluid density, \$C_{\text{d}}\$ is the drag coefficient, \$A\$ is the cross‑sectional area, and \$v\$ is velocity.

As the object speeds up, \$F_{\text{drag}}\$ increases until it balances the weight \$mg\$. At that point, acceleration stops and the object falls at a constant speed – the terminal velocity.

Key Insight: Terminal velocity occurs when the net force is zero:

\$mg = \tfrac{1}{2}\,\rho\,C{\text{d}}\,A\,v{\text{t}}^{2}\$.

Solving for \$v_{\text{t}}\$ gives the speed at which the object stops accelerating.

4. Everyday Examples

  • 🪂 Skydiver: A skydiver initially accelerates, then reaches a constant free‑fall speed (~55 m/s) when drag balances weight.
  • 🍃 Falling leaf: Leaves fall slowly because their small mass and large surface area create high drag, so terminal velocity is low.
  • 🚗 Car braking: The friction between tires and road provides a resistive force that brings the car to a stop.

5. Quick Practice Problems

  1. Calculate the momentum of a 2 kg ball moving at 10 m/s.
  2. If a 70 kg skydiver has a drag coefficient of 1.0 and a cross‑sectional area of 0.7 m², estimate the terminal velocity in air (density ≈ 1.2 kg/m³).
  3. Explain why a heavier object (same shape) reaches a higher terminal velocity than a lighter one.

6. Summary Table

PropertyFormula / Example
Momentum\$p = m\,v\$ (e.g., 2 kg × 10 m/s = 20 kg·m/s)
Drag Force\$F{\text{drag}} = \tfrac{1}{2}\,\rho\,C{\text{d}}\,A\,v^{2}\$
Terminal Velocity\$v{\text{t}} = \sqrt{\dfrac{2mg}{\rho\,C{\text{d}}\,A}}\$

🎉 Remember: When forces balance, motion becomes steady. Understanding how resistive forces work helps predict real‑world behaviours, from falling leaves to skydiving adventures!