A potential divider is a simple circuit that splits an input voltage into smaller, useful voltages. Think of it like a water tap that lets you control how much water comes out – here we control how much electric potential (voltage) we get.
A galvanometer is a tiny device that detects very small electric currents. In a null method, we use it to find the point where no current flows – that’s the “null” point. When the galvanometer reads zero, we know the voltages on either side of the divider are equal.
The galvanometer has a coil in a magnetic field. When current passes through, it deflects. If no current flows, the needle stays still. In a potential divider, we adjust resistor values until the needle is at rest.
The null method is a way to measure unknown voltages or resistances without needing a full-scale meter. By balancing a circuit so that the galvanometer reads zero, we can deduce the unknown value from known components.
If the galvanometer is connected between two points of a potential divider, the condition for a null reading is:
\$\frac{V1}{R1} = \frac{V2}{R2}\$
Where \$V1\$ and \$V2\$ are the voltages across resistors \$R1\$ and \$R2\$ respectively.
If \$R_1\$ is known and the galvanometer is at null, the ratio of voltages equals the ratio of resistances:
\$\frac{V\text{in}}{R1 + R2} = \frac{V\text{in} \cdot R2}{R1 + R_2}\$
Simplifying gives:
\$R2 = R1 \times \frac{V\text{in} - V\text{null}}{V_\text{null}}\$
But at null \$V_\text{null} = 0\$, so we use the ratio directly:
\$\frac{R2}{R1} = \frac{V2}{V1}\$
Since \$V1 + V2 = V\text{in}\$, we can solve for \$R2\$.
Suppose \$V\text{in} = 12\,\text{V}\$, \$R1 = 4.7\,\text{k}\Omega\$, and the galvanometer is centred when \$R_2\$ is set to \$6.3\,\text{k}\Omega\$. Verify the null condition.
| Component | Value |
|---|---|
| \$V_\text{in}\$ | 12 V |
| \$R_1\$ | 4.7 kΩ |
| \$R_2\$ | 6.3 kΩ |
Check the ratio:
\$\frac{R2}{R1} = \frac{6.3}{4.7} \approx 1.34\$
The voltage division gives:
\$V2 = V\text{in} \times \frac{R2}{R1 + R_2} = 12 \times \frac{6.3}{4.7 + 6.3} \approx 7.2\,\text{V}\$
Since \$V_1 = 12 - 7.2 = 4.8\,\text{V}\$, the galvanometer sees equal currents on both sides, confirming the null.
Potential dividers let us split voltages in a predictable way. By using a galvanometer in a null method, we can find the point where no current flows, giving us precise measurements of unknown resistances or voltages. Remember the key equation:
\$\frac{R2}{R1} = \frac{V2}{V1}\$
With practice, you’ll be able to set up and analyse potential divider circuits quickly and accurately. Happy measuring! 🚀