Describe how changing the conditions can change the direction of a reversible reaction for: (a) the effect of heat on hydrated compounds (b) the addition of water to anhydrous compounds limited to copper(II) sulfate and cobalt(II) chloride

Chemical Reactions – Reversible Reactions and Equilibrium

What is a Reversible Reaction?

A reversible reaction is like a see‑saw: the reactants can form products, and the products can turn back into reactants. The reaction stops when the forward and reverse rates are equal – this is called equilibrium. ⚖️

Key Factors that Shift the Equilibrium

  • Change in temperature (heat)
  • Change in concentration of reactants or products
  • Change in pressure (for gases)
  • Adding or removing a solvent (like water)

(a) Effect of Heat on Hydrated Compounds

Hydrated salts contain water molecules that are “glued” to the crystal. When you heat them, the water is released, driving the reaction to the right (toward the anhydrous salt). Think of it as a sponge that dries out when you put it in the sun. 🌞

ReactionDirection at Low TemperatureDirection at High Temperature

\$ \mathrm{CuSO4 \cdot 5H2O} \rightleftharpoons \mathrm{CuSO4} + 5\mathrm{H2O} \$

⇌ (both ways, but more water stays bound) ❄️

⇨ (water leaves, product side dominates) 🔥

\$ \mathrm{CoCl2 \cdot 6H2O} \rightleftharpoons \mathrm{CoCl2} + 6\mathrm{H2O} \$

⇌ (colourful blue crystals) ❄️

⇨ (water leaves, colour changes to white) 🔥

Why does heat favour the product side? The reaction that releases water is endothermic (absorbs heat). Adding heat supplies the energy needed, so the equilibrium shifts to produce more water. This is Le Chatelier’s principle in action. 💡

(b) Adding Water to Anhydrous Compounds

When you sprinkle a little water on dry copper(II) sulfate or cobalt(II) chloride, the salts instantly hydrate and change colour. This is like a dry sponge that instantly soaks up water and changes its appearance. 🧼

Copper(II) Sulfate – \$\ce{CuSO4}\$

  1. Start with anhydrous blue crystals: \$\mathrm{CuSO_4}\$.
  2. Add a few drops of water.
  3. Within seconds, the crystals turn blue‑white and dissolve, forming the pentahydrate: \$ \mathrm{CuSO4 \cdot 5H2O} \$.
  4. Reaction: \$ \mathrm{CuSO4} + 5\mathrm{H2O} \rightleftharpoons \mathrm{CuSO4 \cdot 5H2O} \$.

Cobalt(II) Chloride – \$\ce{CoCl2}\$

  1. Start with anhydrous pink crystals: \$\mathrm{CoCl_2}\$.
  2. Add a few drops of water.
  3. Colour changes to bright blue as the hexahydrate forms: \$ \mathrm{CoCl2 \cdot 6H2O} \$.
  4. Reaction: \$ \mathrm{CoCl2} + 6\mathrm{H2O} \rightleftharpoons \mathrm{CoCl2 \cdot 6H2O} \$.

Why the colour change? The coordination of water molecules around the metal ion alters the way light is absorbed, giving the hydrated salts their distinct colours. Think of it as the metal ion wearing a new “water coat” that changes its appearance. 🎨

Quick Review – What Happens When Conditions Change?

  • Adding heat to a hydrated salt → water is released → equilibrium shifts to the right (more anhydrous salt).
  • Adding water to an anhydrous salt → hydration occurs → equilibrium shifts to the left (more hydrated salt).
  • Both actions are examples of Le Chatelier’s principle: the system resists the change by shifting the reaction direction.

Remember: Equilibrium is not a static point; it’s a dynamic balance. By changing temperature or concentration, you can tip the balance and watch the reaction “choose” a new direction. 🚀